Scala-封闭吗？

Question

I am not sure whether the code I´ve just written can be called a closure, here it is: 我不确定我刚刚编写的代码是否可以称为闭包，这里是：

withExistingDataSource(dataSourceId, dataSource => checkDataSourceTypeAndFetchDataFromAgent(dataSource, theQuery))

See following the previous method signature: 请参阅以下先前的方法签名：

private def withExistingDataSource(dataSourceId: Long, success: DataSource => Result): Result

Can I state that: 我可以声明：

dataSource => checkDataSourceTypeAndFetchDataFromAgent(dataSource, theQuery)

is a closure? 是关闭？

Answer 1

Yes it is. 是的。

The result of the function depends on the theQuery variable which is defined outside the function. 函数的结果取决于在函数外部定义的theQuery变量。