[英]Why can't I unsubscribe from an Event Using a Lambda Expression?
This article states You Can't Unsubscribe from an Event Using a Lambda Expression . 本文说明您无法使用Lambda表达式取消订阅事件 。
Eg you can subscribe as follows: 例如,您可以订阅如下:
d.Barked += (s, e) => Console.WriteLine("Bark: {0}", e);
but you can't unsubscribe like this: 但是你不能这样取消订阅:
d.Barked -= (s, e) => Console.WriteLine("Bark: {0}", e);
Why? 为什么? What's the difference between this and unsubscribing from a delegate, eg
这与代表取消订阅有什么区别,例如
EventHandler<string> handler = (s, e) => Console.WriteLine("Bark: {0}", e);
d.Barked += handler;
// ...
d.Barked -= handler;
It all comes down to: when are two delegates considered the same for the purposes of delegate addition / subtraction. 这一切都归结为:为了代表加法/减法的目的,两位代表何时被认为是相同的。 When you unsubscribe, it is essentially using the logic from
Delegate.Remove
, which considers two delegates equivalent if both the .Target
and the .Method
match (at least, for the simple case of a delegate with a single target method; multicast is more complicated to describe). 当取消订阅时,它基本上使用从逻辑
Delegate.Remove
,它参考等效两位代表如果两个.Target
和.Method
匹配(至少,对于具有单一的目标方法的委托的简单情况;多播是更很难描述)。 So: what is the .Method
and .Target
on a lambda (assuming we are compiling it to a delegate , and not to an expression )? 所以:是什么
.Method
和.Target
在拉姆达(假设我们将它编译成一个代表 ,而不是一个表达式 )?
The compiler actually has a lot of freedom here, but what happens is: 编译器实际上在这里有很多自由,但是会发生什么 :
this
token); this
标记); the target is the reference to this capture-context instance (which will be defined by the capture scope) this
(implicit or explicit), the compiler creates an instance method (the method ) on the current type; this
(隐式或显式)使用每个实例状态,则编译器在当前类型上创建实例方法( 方法 ); the target is the current instance ( this
) this
) What it doesn't do, however, is compare lots of lambdas with similar looking bodies to reduce any. 然而,它没有做的是将许多lambda与具有相似外观的身体进行比较以减少任何。 So what I get when I compile your code is two static methods:
所以我编译代码时得到的是两个静态方法:
[CompilerGenerated]
private static void <Main>b__0(object s, string e)
{
Console.WriteLine("Bark: {0}", e);
}
[CompilerGenerated]
private static void <Main>b__2(object s, string e)
{
Console.WriteLine("Bark: {0}", e);
}
(the Main
here is just because in my test rig those lambdas are inside the Main
method - but ultimately the compiler can choose any unpronounceable names it chooses here) (这里的
Main
是因为在我的测试装备中,那些lambdas在Main
方法中 - 但最终编译器可以选择它在这里选择的任何不可发音的名称)
The first method is used by the first lambda; 第一种方法由第一种lambda使用; the second method is used by the second lambda.
第二种方法由第二种lambda使用。 So ultimately, the reason it doesn't work is because the
.Method
doesn't match. 最终,它不起作用的原因是因为
.Method
不匹配。
In regular C# terms, it would be like doing: 在常规的C#术语中,它会像:
obj.SomeEvent += MethodOne;
obj.SomeEvent -= MethodTwo;
where MethodOne
and MethodTwo
have the same code inside them; 其中
MethodOne
和MethodTwo
包含相同的代码; it doesn't unsubscribe anything. 它没有取消订阅任何东西。
It might be nice if the compiler spotted this, but it is not required to , and as such it is safer that it doesn't elect to - it could mean that different compilers start producing very different results. 如果编译器发现这一点可能会很好 ,但它不是必需的 ,因此它更安全,它不会选择 - 它可能意味着不同的编译器开始产生非常不同的结果。
As a side note; 作为旁注; it could be very confusing if it did try to de-dup, because you'd also have the issue of capture contexts - it would then be the case that it "worked" in some cases and not others - without being obvious which - probably the worst possible scenario.
如果它确实试图去重复它可能会非常混乱,因为你也有捕获上下文的问题 - 那么它会在某些情况下“工作”而不是其他情况 - 而不是显而易见的 - 可能最糟糕的情况。
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