PHP＆MySQLi多次插入-错误

Question

Good Day,

am having difficulty with MySQLi multiple insert. I have this db which consists of 6 different tables each of it has the eid as the foreign key from employees table. Here are the list of the tables: employees (which ofcourse holds the primary key for eid ), then contact , education , job_desc , work_history , familybg

What am having trouble with is when I tried to insert a data taken from the forms of the index page to the insert.php where the MySQLi function's been called out. You could see the code below:

[NOTE: The following attributes are mere dummy.]

insert.php (Revised)

include('db.php');

//build sql statements
<?php

$sql1 = "INSERT INTO employee (fname,mname,
    lname,age,
    gender,birthday,
    birthplace,citizenship,
    status,sss,
    philhealth,tin,
    height,weight) 
        VALUES 
        ('$fname','$mname','$surname',
        '$age','$gender',
        '$birth','$place',
        '$citizen','$civil',
        '$ss','$phil','$tin',
        '$height','$weight')";

        $r1 = mysqli_query($db,$sql1);
        $id = mysqli_insert_id($db);

$sql2 = "INSERT INTO contact (eid,address,province,postcode,telno,mobile,email,alternate)
        VALUES('$id','$address','$province','$postcode','$tel','$mob','$email','$alter')";

$sql3 = "INSERT INTO educ (eid,elem,egrad,highschool,hgrad,college,cgrad) VALUES ('$id','$elem','$egrad','$high','$hgrad','$col','$cgrad')";

$sql4 = "INSERT INTO employment (eid,position,status,hireDate,job_desc,basic,salary) VALUES ('$id','$pose','$stat','$hstart','$dept','$pay','$salary')";

$sql5 = "INSERT INTO work (eid,company_name,position,desc,startDate,endDate) VALUES ('$id','$prev','$pold','$job','$sdate','$edate')";

$sql6 = "INSERT INTO family (eid,fatherName,motherName,sibling,spouse,children) VALUES ('$id','$dad','$mom','$kname','$spouse','$child')";


//returns 1 if sucessful and 0 if not
//mysqli_query($link,$query)

$r2 = mysqli_query($db,$sql2) or die(mysqli_error($db));
$r3 = mysqli_query($db,$sql3) or die(mysqli_error($db));
$r4 = mysqli_query($db,$sql4) or die(mysqli_error($db));
$r5 = mysqli_query($db,$sql5) or die(mysqli_error($db));
$r6 = mysqli_query($db,$sql6) or die(mysqli_error($db));

$sqlResult = $r2 && $r3 && $r4 && $r5 && $r6;


//commit the queries if no errors otherwise rollback
if(!$sqlResult){
//sqlResult = 0, thus there was a problem
mysqli_rollback($db);
echo "ERROR: Could not save data!";


}else{
//sqlResult = 1, no problem
mysqli_commit($db);
echo "Record saved!";
}


mysqli_close($db);

?>

The output shows: ERROR: Could not save data! when I tried to run the program. It only implies that the insert statement couldn't proceed and thus returns to the mysqli_rollback(); At first I thought perhaps it has something to do with the quotes, but after a dozen of times of checking finally I don't see it as the culprit. But if that is not the issue then I wonder what was it? You know am just a beginner with MySQLi. So if anyone who has broader knowledge about it and will give me some piece of advice will be appreciated.

(Current) Issue #2:

After a long series of debugging, the mysqli multiple insert finally works with the exception of the foreign key. When I checked the table for contact which is next to the employees table the column for eid successfully recorded the exact value of the eid from employees table, but the rest of the table displays 0 for eid column. Anyone who knows how to deal with it? Thanks in advance.

NOTE: Kindle checked the revised code above to see the changes and to see the current issue the codes are having.

Answer 1

The order you are running the queries is not good. You have to do the query before using mysqli_insert_id() function to get the last inserted id.

• $surname is duplicated in first statement

Do it like this:

//build sql statements
$sql1 = "INSERT INTO employees (fname,mname,
    lname,age,
    gender,birthday,
    birthplace,
    height,weight) 
        VALUES 
        ('$fname','$mname',
        '$surname','$surname',
        '$age','$gender',
        '$birth','$place',
        '$height','$weight')";

$r1 = mysqli_query($db,$sql1);
$id = mysqli_insert_id();


$sql2 = "INSERT INTO contact (eid,address,province,postcode,telno,mobile,email,alternate)
        VALUES('$id','$address','$province','$postcode','$telno','$mob','$email','$alter')";

$sql3 = "INSERT INTO education (eid,elem,egrad,high,college,cgrad) VALUES ('$id','$elem','$egrad','$high','$col','$cgrad')";

$sql4 = "INSERT INTO job_desc (eid,position,status,hireDate,department,job_desc,basic,salary) VALUES ('$id','$pose','$stat','$hstart','$dept','$pay','$salary')";

$sql5 = "INSERT INTO work_history (eid,company_name,position,desc,startDate,endDate) VALUES ('$id','$prev','$pold','$job','$sdate','$edate')";

$sql6 = "INSERT INTO familybg (eid,fatherName,motherName,sibling,spouse,children) VALUES ('$id','$dad','$mom','$kname','$spouse','$child')";


$r2 = mysqli_query($db,$sql2);
$r3 = mysqli_query($db,$sql3);
$r4 = mysqli_query($db,$sql4);
$r5 = mysqli_query($db,$sql5);
$r6 = mysqli_query($db,$sql6);

Answer 2

In statement one you have an column to much:

 $sql1 = "INSERT INTO employees (fname,mname,
        lname,age,
        gender,birthday,
        birthplace,
        height,weight) 
            VALUES 
            ('$fname','$mname',
            '$surname','$surname', 
            '$age','$gender',
            '$birth','$place',
            '$height','$weight')";
            $id= mysqli_insert_id($db);

surname is twice in values!

Instatement 4

$sql4 = "INSERT INTO job_desc (eid,position,status,hireDate,department,job_desc,basic,salary) VALUES ('$id','$pose','$stat','$hstart','$dept','$pay','$salary')";

is the value for column job_desc missing

Answer 3

You query for job_desc table is wrong.

$sql4 = "INSERT INTO job_desc (eid,position,status,hireDate,department,job_desc,basic,salary)                              VALUES ('$id','$pose','$stat','$hstart','$dept','$pay','$salary')";

In Values you forgot to give value for job_desc.