如何在Python中（推送）解析XML文件？

Question

I've already seen this question , but it's from the 2009.
What's a simple modern way to handle XML files in Python 3?

Ie, from this TLD (adapted from here ):

<?xml version="1.0" encoding="UTF-8" ?>
<taglib>
  <tlib-version>1.0</tlib-version>
  <short-name>bar-baz</short-name>

  <tag>
  <name>present</name>
     <tag-class>condpkg.IfSimpleTag</tag-class>
  <body-content>scriptless</body-content>

  <attribute>
    <name>test</name>
    <required>true</required>
    <rtexprvalue>true</rtexprvalue>
  </attribute>

  </tag> 

</taglib>

I want to parse TLD files (Java Server Pages Tag Library Descriptors), to obtain some sort of structure in Python (I have still to decide about that part).

Hence, I need a push parser. But I won't do much more with it, so I'd rather prefer a simple API (I'm new to Python).

Answer 1

xml.etree.ElementTree is still there, in the standard library:

import xml.etree.ElementTree as ET

data = """your xml here"""

tree = ET.fromstring(data)
print(tree.find('tag/name').text)  # prints "present"

---

If you look outside of the standard library, there is a very popular and fast lxml module that follows the ElementTree interface and supports Python3:

from lxml import etree as ET

data = """your xml here"""

tree = ET.fromstring(data)
print(tree.find('tag/name').text)  # prints "present"

Besides, there is lxml.objectify that allows you to deal with XML structure like with a Python object.