MySQL ORDER BY两次（通过同一字段）

Question

I have a series of events with dates, as follows:

• Event 1, 1/1/2014
• Event 2, 1/2/2014
• Event 3, 1/3/2014

Say I wanted the most recent two events, in chronological order. If I ran:

SELECT * FROM 'table_name' ORDER BY 'Date' ASC LIMIT 2

I would get the following results:

• Event 1, 1/1/2014
• Event 2, 1/2/2014

But this is incorrect, as Event 3 is the most recent event. So I therefore change ASC to DESC:

SELECT * FROM 'table_name' ORDER BY 'Date' DESC LIMIT 2

And I get the following results:

• Event 3, 1/3/2014
• Event 2, 1/2/2014

This is the correct result set, but they're backwards. I would like the most recent event last...but I can't simply use ORDER BY 'Date' a second time. Is there a way to limit my results (via a LIMIT and an ORDER BY , and then use a second ORDER BY on the remaining results?

Any help is much appreciated!

Answer 1

an even faster way is to just do one select. use UNION syntax to order a second time. try it out!

(SELECT * 
 FROM events 
 ORDER BY date DESC 
 LIMIT 2
)ORDER BY date ASC;

DEMO

Answer 2

SELECT * 
FROM (SELECT * FROM events ORDER BY date DESC LIMIT 2) AS table_alias 
ORDER BY date ASC

You need to have a table alias for a sub query

Cheers

Answer 3

actually, you can

SELECT * FROM (
SELECT * FROM 'table_name' ORDER BY 'Date' DESC LIMIT 2
)
ORDER BY 'Date' ASC