PHP回显行X倍不同的文本

Question

Title might not make complete sense, couldn't think of a way to explain it so I will do a mock PHP example.

<?php
$startNumber = 1;
$endNumber = 15;
$fileExt = '.jpg';
?>

And then on the page it will echo from the $startNumber to the $endNumber in something like a foreach

<?php echo("<img src=\"#.jpg\">"); ?>

Hope this is making sense...

I'd also like to point out that the numbers < 10 start with a 0 so it will need to be in the image source link.

Answer 1

echo is not a function, it's a language construct. Don't use ().

Also you need to use a loop like for() to do that (Also see sidenote of Fred -ii).

$endNumber = 15;
for($i = 1; $i <= $endNumber; $i++) {
    if($i < 10) {
        $i = "0".$i;
    }
    echo "<img src=\"".$i.".jpg\" />";
}

If this is not what you asked, add more information.