[英]How to select table from syntax show on mysql, without using procedure?
i have read this article Select data from “show tables” MySQL query . 我已阅读本文, 从“显示表” MySQL查询中选择数据 。 But i need to get table from show tables. 但是我需要从显示表中获取表。 I try this syntax at the first. 我首先尝试这种语法。
show tables from pos where
tables_in_pos
like (select kdtk from toko) 显示pos中的表,而tables_in_pos
一样(从toko中选择kdtk)
and then the value has show 然后值显示
+-------------------+ + ------------------- +
| | tables_in_pos | table_in_pos |+-------------------+ + ------------------- +
| | fnpk | fnpk |
after that i try this syntax 之后,我尝试这种语法
select * from concat(show tables from pos where
tables_in_pos
like (select kdtk from toko),'a') as Hasil select * from concat(显示pos中的表,其中tables_in_pos
像(从toko中选择kdtk),'a')为Hasil
How to select table from syntax Show on mysql? 如何从MySQL语法显示中选择表? without using Procedure. 不使用过程。
如下使用查询,您需要在查询中包括条件以使其符合您的要求:
SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA='your DB_Name' AND........{additional conditions }....
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