[英]PHP preg_match function get phone number from string
Here is my PHP code. 这是我的PHP代码。 I'm needing a regular expression to get my desired output. 我需要一个正则表达式以获取所需的输出。
$str = 'abc:123,phoneNumber:631 741-4498, fdsfdsf, hgjhtg,juiy';
Expected Output: 631741-4498
预期产量: 631741-4498
$str = 'abc:123,phoneNumber:+123 423, fdsfdsf, hgjhtg,juiy';
Expected Output: +123 423 预期输出: +123 423
$str = 'abc:123,phoneNumber:+(123) 423-727, fdsfdsf, hgjhtg,juiy';
Expected Output: +(123) 423-727 预期输出: +(123)423-727
Here's what I've tried 这是我尝试过的
$str = 'abc:123,phoneNumber:631 741-4498, fdsfdsf, hgjhtg,juiy';
$str = str_replace(" ","",$str);
preg_match('/phoneNumber:\s*(.*)/', $str, $matches);
Change your regular expression to /(\\d+ \\d+\\-\\d+)/
将您的正则表达式更改为/(\\d+ \\d+\\-\\d+)/
<?php
$str = 'abc:123,phoneNumber:631 741-4498, fdsfdsf, hgjhtg,juiy';
preg_match('/(\d+ \d+\-\d+)/', $str, $matches);
print_r($matches[0]);
Change your regular expression to /phoneNumber:[a-zA-Z0-9\\ \\+\\-(\\(\\))]+/
将您的正则表达式更改为/phoneNumber:[a-zA-Z0-9\\ \\+\\-(\\(\\))]+/
<?php
$str = 'abc:123,phoneNumber:631 741-4498, fdsfdsf, hgjhtg,juiy';
preg_match('/phoneNumber:[a-zA-Z0-9\ \+\-(\(\))]+/', $str, $matches);
print_r( str_replace("phoneNumber:", "", $matches[0]) );
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