$ .ajax发布成功后的jQuery Ajax JSON错误报告

Question

EDIT: I fixed the errors with the PHP that have been mentioned in Answers but I still have the same problem.

I'm trying to display an error message if my POST request fails, and to show a success message if it doesn't fail. It currently shows the success message correctly, but nothing happens if I make the sql fail, even in console.

JQUERY: // I have removed unnecessary code

        $("#form").validate({
        ignore:'',
        errorPlacement: function(error, element) {
            error.insertAfter(element.parent()); // <- make sure the error message appears after parent element (after textbox!)
        },
        rules: {
        },
        messages: {
        },
        submitHandler: function(form) { 
            var datastring = $("#form").serialize();
            $.ajax({
            type: "POST",
            url: "myscript.php",
            data: datastring,
            dataType:"json",
            success:  function (response) {
                if(response.status === "success") {
                    window.alert(response.comment);
                } else if(response.status === "error") {
                    window.alert(response.comment);
                }
             }
        }); // close $.ajax
    } // close submit handler 
}); //end validate

PHP:

    if($row = sasql_fetch_array($insert))
{   
    //success message 
    $arr = array ('status'=>'success','comment'=> $custid );
    echo json_encode($arr);


}  else {
    //error message
    $arr = array ('status'=>'error','comment'=>'There has been an error. Please try again.');
    echo json_encode($arr);
}

Does anyone have any ideas about what the issue could be here? Like I said, if I add console.log(JSON.stringify(response)); just after the success function, nothing at all is returned on the error array. Thanks

Answer 1

Problem in your php file. You got syntax error in failure part. But not in success. You used unwanted } and concatenate string using + instead of . operator. Also remove the empty spaces near the array.

    if($row = sasql_fetch_array($insert))
{   
    //success message 
    $arr = array ('status'=>'success','comment'=> $custid );
    echo json_encode($arr);
}

}  else {
    //error message
    $arr = array ('status'=>'error','comment'=>'There has been an error. Please try again.'+$custid);
    echo json_encode($arr);
}

should be

    if($row = sasql_fetch_array($insert))
{   
    //success message 
    $arr = array('status'=>'success','comment'=> $custid );
    echo json_encode($arr);

}  else {
    //error message
    $arr = array('status'=>'error','comment'=>'There has been an error. Please try again.'.$custid);
    echo json_encode($arr);
}

Answer 2

If you look at this line:

$arr = array ('status'=>'error','comment'=>'There has been an error. Please try again.'+$custid);

You'll see that you're using + instead . , which is the concatenation operator in PHP .

Answer 3

it is the correct php code

if($row = sasql_fetch_array($insert))
{   
    //success message 
    $arr = array ('status'=>'success','comment'=> $custid );
    echo json_encode($arr);

}  else {
    //error message
    $arr = array ('status'=>'error','comment'=>'There has been an error. Please try again.' . $custid);
    echo json_encode($arr);
}