AWK-在以pattern开头的列中返回第n个单词

Question

I know I can use awk to get a line starting with expression exp by awk '/^exp/' . How do I get the n-th word from this line?

Answer 1

Use {print $n} in the awk statement

echo "abcd bcd cd d" | awk '/^ab/ { print $3}'

This would echo "cd"

Answer 2

give this a try:

awk -v n="$var" '/^exp/{print $n}' file

$var could be shell variable, the value is the index of your column.

Answer 3

awk '{print $n}'打印出该行中的第n个单词吗？