如何使用sed，awk或grep等Linux程序从HTML选择列表中删除唯一值？

Question

I copy the HTML from a select boxes, and trying to figure out a quick way to remove the HTML so I am left with a list of names. Generally it's not a problem, but these have unique values. I would prefer using a program like grep, sed, awk or vi. Right now I have to go through manually and edit each line. Any help would be great, thank you!

<option value="DL_54292">(DL)finance</option>
<option value="DL_54274">(DL)sales</option>
<option value="510496">Ben Smith</option
<option value="510507">Christopher Jones</option>
<option value="510513">Dawn James</option>
<option value="510533">Joe Wilson</option>
<option value="551825">Mark Jackson</option>
<option value="510562">Ronnie Libby</option>

Edit: Output format suggested by Fede.

Trying to get a simple text list, with line feed or carriage return.

finance
sales
Ben Smith
Christopher Jones
Dawn James
Joe Wilson
Mark Jackson
Ronnie Libby

Answer 1

Use grep to get the texts between the tags,

$ grep -oP '(?<=>)[^<>]+' file
(DL)finance
(DL)sales
Ben Smith
Christopher Jones
Dawn James
Joe Wilson
Mark Jackson
Ronnie Libby

Answer 2

Since you mentioned vi, you can use this line

:%s_^<option value=".*">\(.*\)</option>$_\1_gi


%s -> substitute in all the file
^ -> start of line
.* -> any characters
\(.*\) -> any characters, remember those.
$ -> end of line
\1 -> first remembered match
gi -> ingnore case and take all matches in line
_ -> substitution separator

:s is search and replace, s_foo_bar replaces foo by bar in current line

Answer 3

awk can do this:

awk -F"<|>" '{print $3}'
(DL)finance
(DL)sales
Ben Smith
Christopher Jones
Dawn James
Joe Wilson
Mark Jackson
Ronnie Libby

If I should be true to your output request the data in parentheses should be gone too:

awk -F"<|>" '{sub(/[^)]*)/,"",$3);print $3}'
finance
sales
Ben Smith
Christopher Jones
Dawn James
Joe Wilson
Mark Jackson
Ronnie Libby

Answer 4

If you don't mind using Notepad++, then you can use this regex:

.*>(.*)<.*

And replace with \\1