$ exif问题中的PHP语法

Question

Hello would like to know how can I get this syntax correct.

I got this code from: http://php.net/manual/en/function.exif-read-data.php

code below:

<?php

$exif = exif_read_data('tests/test2.jpg', 0, true);
echo "test2.jpg:<br />\n";
foreach ($exif as $key => $section) {
    foreach ($section as $name => $val) {
        echo "$key.$name: $val<br />\n";
    }
}
?>

now I want to add a line which actualy gives you the image name. test1.jpg etcs from php array.

test/<?=$prod['image_url'] ?>

like this

<?php

$exif = exif_read_data('test/<?=$prod['image_url'] ?>', 0, true);
echo "test2.jpg:<br />\n";
foreach ($exif as $key => $section) {
    foreach ($section as $name => $val) {
        echo "$key.$name: $val<br />\n";
    }
}
?>

replacing

tests/test2.jpg

with

test/<?=$prod['image_url'] ?>

but the syntax is incorrect. Please suggest how it can be corrected.

Answer 1

modify

exif_read_data('test/<?=$prod['image_url'] ?>', 0, true);

to

exif_read_data('test/' . $prod['image_url'], 0, true);

Full code

$exif = exif_read_data('test/' . $prod['image_url'], 0, true);
echo "test2.jpg:<br />\n";
foreach ($exif as $key => $section) {
    foreach ($section as $name => $val) {
        echo "$key.$name: $val<br />\n";
    }
}
?>

Error reason : You can't put php tag inside another php tag

Answer 2

ouch. ok, try this. It allows you to use the $prod['image_url'] in the string $filename and then pass $filename to the exif_read_data function.

<?php

$filename = sprintf("tests/%s",$prod['image_url']);

$exif = exif_read_data($filename, 0, true);

printf("%s<br/>",$filename);

foreach ($exif as $key => $section) {
    foreach ($section as $name => $val) {
        echo "$key.$name: $val<br />\n";
    }
}
?>