如果一个单词有5个字母，则每行打印一个单词，如果没有，则仅打印该单词？

Question

import java.util.Scanner;

public class SeperateLetters 
{

    public static void main(String[] args)
    {
        Scanner scan= new Scanner(System.in);
        System.out.println("Enter a word:");
        String w= scan.nextLine();
        for(int i=0; i<w.length();i++)
            System.out.println(w.charAt(i));    
    }
}

This is what I have so far and I can't figure how to make it so that if the word is 5 letters or longer to print it one letter per line and if not to just print the word. So far it'll just print any word with one letter per line.

Answer 1

You are very close. The only thing missing is an if-else conditional statement, to check whether the word has a length of five. Without this check, you will always print the string one character per line, regardless of its length.

import java.util.Scanner;

public class SeperateLetters {

    public static void main(String[] args) {
        Scanner scan= new Scanner(System.in);
        System.out.println("Enter a word:");
        String w = scan.nextLine();
        if (w.length() >= 5) {     // print one char per line if length is 5
            for (int i = 0; i < w.length(); i++)
                System.out.println(w.charAt(i));
        } else {
            System.out.println(w); // otherwise, print the whole string
        }
    }
}

Answer 2

使用if-else语句检查是否w.length() == 5 。

Answer 3

public class SeperateLetters {

public static void main(String[] args)
{
    Scanner scan= new Scanner(System.in);
    System.out.println("Enter a word:");
    String w= scan.nextLine();

    if( w.length() > 5) 
    {    
        for(int i=0; i<w.length();i++) 
        {
            System.out.println(w.charAt(i));
        }    
    }
}

}