[英]Upload a file using the HTTPWebrequest(does not pass, post data)
I Tries to upload a file using the HTTPWebrequest(multipart/form-data). 我尝试使用HTTPWebrequest(multipart / form-data)上传文件。
So I see a few pages, and wrote the following code : 因此,我看到了几页,并编写了以下代码:
var boundary = "----------" + DateTime.Now.Ticks.ToString("x");
byte[] boundaryBytes = Encoding.ASCII.GetBytes(boundary);
var template = boundary + "\r\n" +
"Content-Disposition: form-data; name=\"{0}\"" + "\r\n\r\n" +
"{1}\r\n";
// Request Header
HttpWebRequest req = (HttpWebRequest)WebRequest.Create("http://domain.com/test.php");
req.Method = "POST";
req.KeepAlive = true;
req.ContentType = "multipart/form-data; boundary=" + boundary;
req.CookieContainer = COOKIE;
Stream ms = new MemoryStream();
string formItem;
byte[] formItemBytes;
string fileName = Path.GetFileName(@"C:\Users\Username\Image.jpg");
// POST Data
formItem = string.Format(template, "Filename", fileName);
formItemBytes = Encoding.UTF8.GetBytes(formItem);
ms.Write(formItemBytes, 0, formItemBytes.Length);
formItem = string.Format(template, "Username", "RedPetals");
formItemBytes = Encoding.UTF8.GetBytes(formItem);
ms.Write(formItemBytes, 0, formItemBytes.Length);
var headerTemplate = "\r\nContent-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\nContent-Type: application/octet-stream\r\n\r\n";
string header = string.Format(headerTemplate, "Image", fileName);
byte[] headerBytes = Encoding.UTF8.GetBytes(header);
ms.Write(boundaryBytes, 0, boundaryBytes.Length);
ms.Write(headerBytes, 0, headerBytes.Length);
using (FileStream fs = new FileStream(filePath, FileMode.Open, FileAccess.Read))
{
byte[] buffer = new byte[1024];
int bytesRead = 0;
while ((bytesRead = fs.Read(buffer, 0, buffer.Length)) != 0)
{
ms.Write(buffer, 0, bytesRead);
}
}
byte[] boundaryEndBytes = Encoding.ASCII.GetBytes(boundary + "--");
ms.Write(boundaryEndBytes, 0, boundaryEndBytes.Length);
req.ContentLength = ms.Length;
ms.Position = 0;
byte[] tempBuffer = new byte[ms.Length];
ms.Read(tempBuffer, 0, tempBuffer.Length);
ms.Close();
using(Stream rs = req.GetRequestStream())
{
rs.Write(tempBuffer, 0, tempBuffer.Length);
}
HttpWebResponse response = (HttpWebResponse)req.GetResponse();
string result = "";
if (response.StatusCode == HttpStatusCode.OK)
{
Stream resStream = response.GetResponseStream();
StreamReader readStream = new StreamReader(resStream, Encoding.UTF8);
result = readStream.ReadToEnd();
Console.Write(result);
resStream.Close();
readStream.Close();
}
But does not pass POST data.. Is there a part I missed? 但是不会传递POST数据。我错过了一部分吗?
HttpAnalyzer Post 'Data' (Formdata tab is 'No data to display') : HttpAnalyzer发布“数据” (Formdata选项卡为“无数据可显示”):
----------8d1984e7dd49750 ---------- 8d1984e7dd49750
Content-Disposition: form-data; 内容处置:表单数据; name="Filename"
NAME = “文件名”
Image.jpg image.jpg的
----------8d1984e7dd49750 ---------- 8d1984e7dd49750
Content-Disposition: form-data; 内容处置:表单数据; name="Username"
NAME = “用户名”
RedPetals RedPetals
----------8d1984e7dd49750 ---------- 8d1984e7dd49750
Content-Disposition: form-data; 内容处置:表单数据; name="img";
NAME = “IMG”; filename="Image.jpg"
文件名= “image.jpg的”
Content-Type: application/octet-stream 内容类型:应用程序/八位字节流
??? ???
----------8d1984e7dd49750-- ---------- 8d1984e7dd49750--
Response result : 回应结果 :
// echo var_dump($_POST); // echo var_dump($ _ POST); echo var_dump($_FILES);
回声var_dump($ _ FILES);
array(0) { } array(0) { } 数组(0){}数组(0){}
//var boundary = "----------" + DateTime.Now.Ticks.ToString("x");
var boundary = "--------" + DateTime.Now.Ticks.ToString("x");
// var template = boundary + "\r\n" +
// "Content-Disposition: form-data; name=\"{0}\"" + "\r\n\r\n" +
// "{1}\r\n";
var template = "--" + boundary + "\r\n" +
"Content-Disposition: form-data; name=\"{0}\"" + "\r\n\r\n" +
"{1}\r\n";
Here's my solution when I encountered this issue: 这是我遇到此问题时的解决方案:
Client: 客户:
public async Task UploadImage(byte[] image, string url)
{
Stream stream = new System.IO.MemoryStream(image);
HttpStreamContent streamContent = new HttpStreamContent(stream.AsInputStream());
Uri resourceAddress = null;
Uri.TryCreate(url.Trim(), UriKind.Absolute, out resourceAddress);
Windows.Web.Http.HttpRequestMessage request = new Windows.Web.Http.HttpRequestMessage(Windows.Web.Http.HttpMethod.Post, resourceAddress);
request.Content = streamContent;
var httpClient = new Windows.Web.Http.HttpClient();
var cts = new CancellationTokenSource();
Windows.Web.Http.HttpResponseMessage response = await httpClient.SendRequestAsync(request).AsTask(cts.Token);
}
Controller: 控制器:
public async Task<HttpResponseMessage> Post()
{
Stream requestStream = await this.Request.Content.ReadAsStreamAsync();
byte[] byteArray = null;
using (MemoryStream ms = new MemoryStream())
{
await requestStream.CopyToAsync(ms);
byteArray = ms.ToArray();
}
.
.
.
return Request.CreateResponse(HttpStatusCode.OK);
}
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