简体   繁体   English

JS:如何在数组中使用一个元素然后摆脱它

[英]JS: How do I use an element in an array and then get rid of it

I'm trying to make a matching card game and trying to 'shuffle' my cards. 我正在尝试制作匹配的纸牌游戏,并试图“洗牌”我的纸牌。 Here is how I have everything set up right now: 这是我现在设置的所有内容的方式:

Cards' data are objects 卡的数据是对象

var idea = {
    id: 1,
    english: 'idea',
    pinyin: 'zhǔyì',
    hanyu: '主意'
}

The "deck" is an array with all the cards. “卡座”是包含所有卡的阵列。

var vocabArray = [idea, getOn, need, getOff, beautiful, scenery, sameAlike, because, help, play];

This is how the cards are getting into my HTML. 这就是卡片进入我的HTML的方式。

var cardIndexNum = Math.floor(Math.random() * 10);
var cardReturn = vocabArray[cardIndexNum];
document.getElementById('card1').innerHTML = '<h2>' + cardReturn.hanyu + '<br>' + cardReturn.pinyin + '</h2>';

HTML 的HTML

div class='card' id='card1'>
    JAVASCRIPT PUTS CARD INFO AND H TAGS HERE
</div>

Right now I some cards are appearing more than once because after I use the card it is still in the array. 现在,有些卡不止一次出现,因为使用卡后它们仍在阵列中。 I tried using .splice on the cards after they were used, but then I would sometimes get an array element with undefined attributes. 使用卡后,我尝试在卡上使用.splice,但是有时我会得到带有未定义属性的数组元素。

Since it is a array of objects , you can't use splice directly over the array inorder to remove the element. 由于它是一个对象数组 ,因此不能直接在数组上使用拼接来删除元素。

(this example uses jQuery ) (此示例使用jQuery

var findAndRemove = function(array,  property, value) {
    $.each(array, function(index, result) {
          if(result[property] == value) {
              array.splice(index, 1);
          }
    }
}

You need to pass vocabArray and id and value as function parameter 您需要传递vocabArray以及idvalue作为函数参数

findAndRemove(vocabArray, "id", 1);

EDIT 编辑

To support normal javascript 支持普通的javascript

(NOT TESTED) (未测试)

var findAndRemove = function(array, value) {
    for(var i=0; i < array.length; i++) {
          if(array[i].id == value) {
              array.splice(i, 1);
          }
    }
}

Call by 致电者

findAndRemove(vocabArray, 1);

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM