Python：将函数传递给具有命名参数的函数

Question

I am looking to pass a function to another function, as well as a named parameter. This is similar to the question asked here , except that it doesn't address named parameters. A question was asked about it in the comments but no reply.

Example:

def printPath(path, displayNumber = False):
    pass

def explore(path, function, *args):
    contents = function(*args)

print explore(path, printPath, path, displayNumber = False)

This gives the error:

TypeError: explore() got an unexpected keyword argument 'displayNumber'

Answer 1

You just have to allow explore to receive named parameters as well:

def printPath(path, displayNumber = False):
    pass

def explore(path, function, *args, **kwargs):
    contents = function(*args, **kwargs)

print explore(path, printPath, path, displayNumber = False)