如何在 android 中使用深层链接启动应用程序

Question

I want to launch app using my own app but not by giving the package name, I want to open a custom URL.

I do this to start an application.

Intent intent = getPackageManager().getLaunchIntentForPackage(packageInfo.packageName);
startActivity(intent);

Instead of package name is it possible to give a deep-link for example:

"mobiledeeplinkingprojectdemo://product/123"

Reference

Answer 1

You need to define a activity that will subscribe to required intent filters:

<activity
            android:name="DeepLinkListener"
            android:exported="true" >

            <intent-filter>
                <action android:name="android.intent.action.VIEW" />
                <category android:name="android.intent.category.DEFAULT" />
                <category android:name="android.intent.category.BROWSABLE" />      
                <data
                    android:host="host"
                    android:pathPattern="some regex"
                    android:scheme="scheme" />
            </intent-filter>
        </activity>

Then in onCreate of your DeepLinkListener activity you can access the host,scheme etc:

protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
Intent deepLinkingIntent= getIntent();
deepLinkingIntent.getScheme();
deepLinkingIntent.getData().getPath();
}

perform check on path and again fire a intent to take the user to corresponding activity. refer data for more help

Now fire a Intent:

Intent intent = new Intent (Intent.ACTION_VIEW);
intent.setData (Uri.parse(DEEP_LINK_URL));

Answer 2

Don't forget to handle the exception. If there is no activity that can handle the deep link, startActivity will return an exception.

    try {
    context.startActivity(
        Intent(Intent.ACTION_VIEW).apply {
            data = Uri.parse(deepLink)
        }
    )
} catch (exception: Exception) {
    Toast.makeText(context, exception.localizedMessage, Toast.LENGTH_LONG).show()
}