Excel：如何在一行中查找最后一个“有效”值

Question

I have a workbook of the following style:

| A    | B    | C    |
| 1    | y    |      |
| 2    | y    |      |
| 3    | n    |      |
| 4    | y    |      |
| 5    | n    |      |
| 6    | n    |      |
| 7    | y    |      |

In column CI want to have the last value from column A above the current row which has "y" in column B.

So, the expected output would be:

| A    | B    | C    |
| 1    | y    | ---  |
| 2    | y    | 1    |
| 3    | n    | 2    |
| 4    | y    | 2    |
| 5    | n    | 4    |
| 6    | n    | 4    |
| 7    | y    | 4    |

NB: I actually want to do this is Google Sheets, but I guess an ordinary Excel function would suffice.

Thanks a lot!

Answer 1

Your formula must check the "y" in the row previous, so in C2, you need to reference the string in B1, and either use the number in A1, or the previously selected value in column C.

So the formula is:

=if(B1="y",A1,C1)

Here's a screenshot of what it would look like:

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Based on comment by OP, here is another screenshot showing exactly the output as requested in the question above:

Answer 2

Put the following formula into cell C2 , its an array formula so dont include the curly braces but press CTRL + SHIFT + ENTER to confirm the formula (instead of just ENTER )

{=MAX(($B$1:$B1="y")*$A$1:$A1)}

You can drag that formula down. I haven't tested this on Google Docs, but it works with excel.

Answer 3

请尝试，在C2中复制下来：

=IF(B1="y",MAX(A$1:A1),C1)