如何将日期格式化为以下格式day.month.year？

Question

I need to format a date to following format: 10.12.2014 and I am using the following code but it returns following error

   Messages:    
   Unparseable date: "2014-12-10"

Code

   SimpleDateFormat formatter = new SimpleDateFormat("dd.mm.yyyy");
   Date date = formatter.parse(param.getFromDate());
   String formattedDate = formatter.format(date);

Answer 1

Unparseable date means your input dateString value is not in the same format as expected. For example , if your dateString is 2014-12-10 ( yyyy-MM-dd ) , if you try to format it to dd-MM-yyyy , then this exception will occur.

The following code will help you.!

// Existing date is in this format : "2014-12-10"
SimpleDateFormat formatFrom = new SimpleDateFormat("yyyy-MM-dd");

// Required date is in this format : 10.12.2014
SimpleDateFormat formatTo = new SimpleDateFormat("dd.MM.yyyy");

// Convert the String  param.getFromDate()==>2014-12-10 to a Date
Date date = formatFrom .parse(param.getFromDate());

// Convert Date to String 10.12.2014
String formattedDate = formatTo .format(date);

Answer 2

Change your date format, you are parsing yyyy-MM-dd and providing format as yyyy.MMMM.dd :-

 SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
 Date date = formatter.parse(param.getFromDate());
 String formattedDate = formatter.format(date);

Edit:- you updated format input to dd.mm.yyyy , which again is wrong, and above solution is valid in this case too.

Also you want the date output as 10.12.2014 , which you can do by creating new formatter and parsing the date to string using it:-

formatter = new SimpleDateFormat("dd.MM.yyyy");
String formattedDate2 = formatter.format(date); // 

Answer 3

check this out: Java Docs for SimpleDateFormat

contains all the pattern letters for date and time, helped me a lot when i was looking onto how to implement date and time in my app.