没有模型的MVC 5 Html.BeginForm

Question

I have a simple search form on my _Layout page.

How can I easily pass the value from search-fld to the controller? Without having to create a Model or ViewModel.

@using (Html.BeginForm("Search", "Home", new { id = "search-fld" }, FormMethod.Post, new { @class = "header-search pull-right" }))
{
    @Html.AntiForgeryToken()

    <input type="text" placeholder="Search" id="search-fld">
    <button type="submit">
        <i class="fa fa-search"></i>
    </button>
}

If I run this then "search-fld" get send to the controller (offcourse)

Use Ajax form instead and get the value with Jquery?

Answer 1

Simply by giving your input a name attribute:

<input type="text" placeholder="Search" id="search-fld" name="searchValue">

Then matching that name with a parameter in your controller HttpPost method:

[HttpPost]
public ActionResult Search(string searchValue)

Answer 2

You can use an Ajax call like that :

 $(document).ready(function() {
$("#yourButton").click(function () {
            var yourValue = $("#search-fld").val() ;
            var url = "Search/asd/";
            $.ajax({
                url: url,
                cache: false,
                type: 'POST',
                data: {
                    searchValue = yourValue
                }
                success: function (data) {
                    if (data === true) {
                        alert('Success');
                    } else {
                        alert('Failed');
                    }
                    }
                })
            })
        })

And Your Method in controller :

[HttpPost]
public ActionResult asd(string searchValue)
{

}