返回从循环中调用的数据库查询中检索的数据的问题

Question

I making multiple mongoDB queries in loop. and want to send the all results as one data array.But when I simple use the return for send the data it simply return undefined and do not wait for results of all DB request. I also tried to use q.moulde but same issue.

Code:

var getPrayerInCat = function(data){
    var result ;
    var finalData = [];
    if(data.length >0){
             data.forEach(function(data2){
                 var id= data2.id;
                 Prayer.find({prayerCat:id},function(err,prayer){
                     var deferred = Q.defer()
                     if (err) { // ...
                         console.log('An error has occurred');
                         // res.send(err);
                         result= finalData = err
                     } else {
                         if(!prayer){
                             // console.log(data2.id+'--0');
                             data2.prayersCount = 0;
                             result = deferred.resolve(finalData.push(data2))
                         } else {
                             // console.log(data2.id+'--'+prayer.length);
                             data2.prayersCount = prayer.length;
                             // console.log(prayer)
                             result =  deferred.resolve(finalData.push(data2))
                         } // else for data forward
                     }
                     deferred.promise;
                 })
                // deferred.resolve(finalData);

             })
             /*if(finalData.length > 0) { return finalData;}*/
        }
}

finalData is returned undefined.

Answer 1

Let's start with the general rule for using promises:

Every function that does something asynchronous must return a promise

Which functions are these in your case? It's getPrayerInCat , the forEach callback, and Prayer.find .

Hm, Prayer.find doesn't return a promise, and it's a library function so we cannot modify it. Rule 2 comes into play:

Create an immediate wrapper for every function that doesn't

In our case that's easy with Q's node-interfacing helpers :

var find = Q.nbind(Prayer.find, Prayer);

Now we have only promises around, and do no more need any deferreds. Third rule comes into play:

Everything that does something with an async result goes into a .then callback

…and returns the result. Hell, that result can even be a promise if "something" was asynchronous! With this, we can write the complete callback function:

function getPrayerCount(data2) {
    var id = data2.id;
    return find({prayerCat:id})
//  ^^^^^^ Rule 1
    .then(function(prayer) {
//  ^^^^^ Rule 3
        if (!prayer)
            data2.prayersCount = 0;
        else
            data2.prayersCount = prayer.length;
        return data2;
//      ^^^^^^ Rule 3b
    });
}

Now, we have something a bit more complicated: a loop. Repeatedly calling getPrayerCount() will get us multiple promises, whose asynchronous tasks run in parallel and resolve in unknown order. We want to wait for all of them - ie get a promise that resolves with all results when each of the tasks has finished.

For such complicated tasks, don't try to come up with your own solution:

Check the API of your library

And there we find Q.all , which does exactly this. Writing getPrayerInCat is a breeze now:

function getPrayerInCat(data) {
    var promises = data.map(getPrayerCount); // don't use forEach, we get something back
    return Q.all(promises);
//  ^^^^^^ Rule 1
}

If we needed to do anything with the array that Q.all resolves to, just apply Rule 3.