[英]Matlab: Find minimum value from a set of values for each column in an array
I have a 2-D array A=zeros(1000,1024)
. 我有一个二维数组A=zeros(1000,1024)
。 I want to iteratively compute the difference between each of the value of the i-th row (with i=1-999) and the values of 1000th row. 我想迭代计算第i行的值(i = 1-999)与第1000行的值之间的差。
Right now I think of looping over the 1-999 rows, compute the differences of the current row and the 100th row and store it in a seperaate data structure ( B=zeros(999,1024)
). 现在,我想遍历1-999行,计算当前行与第100行的差,并将其存储在单独的数据结构中( B=zeros(999,1024)
)。 After, I compute the minimum of each column using another for-loop, which iterates over the columns of B
. 之后,我使用另一个for循环计算每个列的最小值,该循环遍历B
的列。
Do you know of a more efficient, faster approach? 您知道更有效,更快捷的方法吗?
如果只希望每列的最小值,那么可以通过在最后进行减法来节省许多操作:
min(A(1:end-1,:),[],1) - A(end,:)
Try this - 尝试这个 -
min(bsxfun(@minus,A(1:999,:),A(1000,:)),[],1)
It seems you want to subtract from the last row, so you can make it general - 看来您想从最后一行中减去,因此可以将其设为通用-
min(bsxfun(@minus,A(1:end-1,:),A(end,:)),[],1)
This is a classic use case for bsxfun
: 这是bsxfun
的经典用例:
M = rand(1000,1024);
V = M(end,:);
MminusV = bsxfun(@minus, M(1:end-1,:), V);
min(MminusV)
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