C中的链表实现

Question

I am new to Linked LIsts and I am trying to implement a Linked List in C . Below in my code :-

#include<stdio.h>
#include<stdlib.h>

struct node {
    int data;
    struct node *next;
};
void insert (struct node *head, int data);
void  print  (struct node *head);
int main()
{
    struct node *head ;
    head= NULL;
    printf("new\n");
    insert(head,5);
    printf("%d\n",head);
    insert(head,4);
    insert(head,6);
    print(head);
    print(head);
    print(head);


} 
void  insert(struct node *head,int data){

    printf("%d\n",head);
    if(head == NULL){
        head =malloc(sizeof(struct node));
        head->next = NULL;
        head->data = data;

    }
    else {
        printf("entered else\n");
        struct node *tmp = head;
        if(tmp->next!=NULL){
            tmp = tmp->next;
        }
        tmp->next  = malloc(sizeof(struct node));
        tmp->next->next = NULL;
        tmp->next->data = data;

    }

}


void print (struct node *head) {
    printf("%d\n",head);
    struct node *tmp = head;
    if (head == NULL) {
        printf("entered null\n");
        return;
    }
    while (tmp != NULL) {
        if (tmp->next == NULL) {
            printf("%0d", tmp->data);
        } else {
            printf("%0d -> ", tmp->data);
        }
        tmp = tmp->next;
    }
    printf("\n");
}

When I run this code the output is :-

new
0
0
0
0
0
entered null
0
entered null
0
entered null

The head is always null and it doesnt update the null . It doesnt enter into the else loop in insert . Can anyone help me fix this please . Point out the mistake I am doing . thanks

Answer 1

There may be other errors in your code, but one big issue is that you are attempting to set a head node in insert , but that only affects a local copy of the pointer passed in, so it has no effect in the caller side:

void  insert(struct node *head,int data){
  ....
  head = malloc(sizeof(struct node)); // head is local, caller won't see this

You also need to ensure that when you pass a node that is not NULL , you actually attatch the new node to the head. You can fix the first problem by passing a pointer to a pointer, or by returning the set pointer. For example,

void insert(struct node **head, int data) {
  if(*head == NULL) {
    // create the head node
    ...
    *head = malloc(sizeof(struct node)); 
    ....
  else {
    // create a new node and attach it to the head
    struct node* tmp = malloc(sizeof(struct node));
    ....
    (*head)->next = tmp;
  }
}

Then, in main , you need to pass a pointer to the head pointer, ie use the address-of operator & :

struct node *head = NULL;
insert(&head, 5);

---

Note part of the problem is that the function is trying to do too much. It is called insert , but it attempts to create a new node if the pointer passed in is NULL . It would be better to separate these responsibilities:

// allocate a node and set its data field
struct node* create_node(int  data)
{
  struct node* n = malloc(sizeof(struct node));
  n->next = NULL;
  n->data = data;
  return n;
}

// create a node and add to end node.
// return the new end node.
// end has to point to a valid node object.
struct node* append_node(struct node* tail, int node_data)
{
  struct node* new_tail = create_node(node_data);
  tail->next = new_tail;
  return new_tail;
}

Answer 2

I have fixed your insert function:

#include<stdio.h>
#include<stdlib.h>

struct node {
    int data;
    struct node *next;
};
#define CREATENODE malloc(sizeof(struct node))
void insert (struct node *head, int data);
void  print  (struct node *head);
int main()
{
    struct node *head ;
    head = CREATENODE;
    printf("new\n");
    insert(head,5);
    insert(head,4);
    insert(head,6);
    print(head);
    print(head);
    print(head);


} 
void  insert(struct node *head,int data){
    struct node *temp, *nn;
    for(temp=head;temp->next!=NULL;temp=temp->next);
    nn=CREATENODE;
    nn->data = data;
    nn->next =temp->next;
    temp->next = nn;
}


void print (struct node *head) {
    struct node *tmp = head->next;
    if (head == NULL) {
        printf("entered null\n");
        return;
    }
    while (tmp != NULL) {
        if (tmp->next == NULL) {
            printf("%0d", tmp->data);
        } else {
            printf("%0d -> ", tmp->data);
        }
        tmp = tmp->next;
    }
    printf("\n");
}

Answer 3

void insert(struct node &head,int data){ // pass reference rather than pointer ^ You passed a pointer, but that will only allow you to change the data it is pointing to. In order to change the pointer itself, you have to pass a reference. Not sure my C isn't a bit rusty, but I'm just pointing you in the right direction....

Regards,

André