[英]How to split a string with dynamic integer delimiter inside this string in PHP?
Hex string looks like:十六进制字符串如下所示:
$hexString = "0307wordone0Banotherword0Dsomeotherword";
$wordsCount= hexdec(substr($hexString , 0, 2));
First byte ( 03
) is total number of words in string.第一个字节 (
03
) 是字符串中的总字数。 Next byte is count for characters of the first word ( 07
).下一个字节是第一个字 (
07
) 的字符计数。 And after 7 bytes there is another integer 0B
which tells that next word length is 11 ( 0B
) characters, and so on...在 7 个字节之后,还有另一个整数
0B
表示下一个字长是 11 ( 0B
) 个字符,依此类推...
What should function for exploding such string to array look like?将此类字符串分解为数组的函数应该是什么样的? We know how many iterations there should be from
$wordsCount
.我们知道
$wordsCount
应该有多少次迭代。 I've tried different approaches but nothing seems to work.我尝试了不同的方法,但似乎没有任何效果。
This can be parsed with a simple for
loop in O(n) .这可以用O(n) 中的简单
for
循环解析。 No need for some fancy (and slow) regex solutions.不需要一些花哨的(和缓慢的)正则表达式解决方案。
$hexString = "0307wordone0Banotherword0Dsomeotherword";
$wordsCount = hexdec(substr($hexString, 0, 2));
$arr = [];
for ($i = 0, $pos = 2; $i < $wordsCount; $i++) {
$length = hexdec(substr($hexString, $pos, 2));
$arr[] = substr($hexString, $pos + 2, $length);
$pos += 2 + $length;
}
var_dump($arr);
you can solve this by iterating a pointer on the string with a for loop.您可以通过使用 for 循环迭代字符串上的指针来解决此问题。
$hexString = "0307wordone0Banotherword0Dsomeotherword";
$wordsCount= hexdec(substr($hexString , 0, 2));
$pointer = 2;
for($i = 0; $i<$wordsCount;$i++)
{
$charCount =hexdec(substr($hexString , $pointer, 2 ));
$word = substr($hexString , $pointer + 2, $charCount);
$pointer = $pointer + $charCount + 2;
$words[] = $word;
}
print_r($words);
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