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如何在Arduino中将char转换为int

[英]How to convert a char to int in Arduino

I receive some data in a char variable, and the result in teststring is always a number. 我在char变量中收到一些数据,teststring中的结果总是一个数字。 How can I convert this number to a variable int? 如何将此数字转换为变量int?

After that I can put the int variable on delay time. 之后我可以把int变量放在延迟时间上。 There is a piece of my code: 有一段我的代码:

String readString = String(30);
String teststring = String(100);
int convertedstring;

teststring = readString.substring(14, 18); (Result is 1000)

digitalWrite(start_pin, HIGH);
delay(convertedstring); // Result of teststring convert
digitalWrite(start_pin, LOW);

Use: 使用:

long number = atol(input); // Notice the function change to atoL

Or, if you want to use only positive values: 或者,如果您只想使用正值:

Code: 码:

unsigned long number = strtoul(input, NULL, 10);

Reference: http://www.mkssoftware.com/docs/man3/atol.3.asp 参考: http//www.mkssoftware.com/docs/man3/atol.3.asp

Or, 要么,

int convertedstring = atoi(teststring.c_str());

Do you have access to the atoi function in your Arduino environment? 您是否可以访问Arduino环境中的atoi功能?

If not, you can just write some simple conversion code in there: 如果没有,你可以在那里写一些简单的转换代码:

int my_atoi(const char *s)
{
    int sign=1;
    if (*s == '-')
        sign = -1;
    s++;
    int num = 0;
    while(*s)
    {
        num = ((*s)-'0') + num*10;
        s++;
    }
    return num*sign;
}

String to Long Arduino IDE: 字符串到Long Arduino IDE:

    //stringToLong.h

    long stringToLong(String value) {
    long outLong=0;
        long inLong=1;
        int c = 0;
        int idx=value.length()-1;
        for(int i=0;i<=idx;i++){

            c=(int)value[idx-i];
            outLong+=inLong*(c-48);
            inLong*=10;
        }
        return outLong;
    }

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