c ++多态性和虚函数

Question

Is it possible to call the virtual function foo( int ) from B without using what is done in comment ?

class A {
public: 

    virtual void foo ( char * ) {
    }

    virtual void foo ( int ) {
    }
};

class B : public A {
public:

    void foo ( char * ) {
    }

    //void foo ( int i ) {
    //  
    //  A::foo(i);
    //}
};

B b;
b.foo(123); // cannot convert argument 1 from 'int' to 'char *'

Answer 1

Yes, it is possible. The problem here is that the function B::foo(char*) hides the name of the inherited function A::foo(int) , but you can bring it back into scope of B with a using declaration:

class B : public A {
public:

    void foo ( char * ) {
    }

    using A::foo;
};