在单个scanf中多次扫描字符和整数

Question

int main()
{
int a,i;
 char b;
for(i=0;i<3;i++)
 scanf("%c %d",&a,&b);

} }

The program only scans twice (each for char and int) and then terminates. 该程序仅扫描两次（每次扫描char和int），然后终止。

OUTPUT 输出值

r [R

3 3

4 4

t Ť

Now program is terminating rather than scanning two more times(one char and one int) 现在程序终止而不是再扫描两次（一个字符和一个整数）

Answer 1

scanf(" %c %d",&a,&b);

解决问题

Answer 2

The program scan twice because you tell him to with i < 3 . 该程序扫描两次，因为您告诉i < 3 。 Change the 3 to 5 to scan 4 times. 将3更改为5以扫描4次。