[英]ERROR org.hibernate.util.JDBCExceptionReporter - Data truncated for column 'type'
I am new to Hibernate and working on a test project, I have tried a lot of things to get this example working. 我是Hibernate的新手,正在从事测试项目,我已经尝试了很多方法来使此示例正常工作。 But I am unsure why it fails, I am aware that the null pointer exception could be because I am trying to getQuestions on Survey but its empty.
但是我不确定为什么失败,我知道空指针异常可能是因为我试图在Survey上获取问题,但它为空。 But I have seen so many tutorials online and followed them and all have the same approach.
但是我在网上看到了如此多的教程,并且按照它们进行学习,并且都采用相同的方法。 I have tried recreating the database tables, different versions of hibernate.
我尝试过重新创建数据库表(休眠的不同版本)。 Nothing has helped me get this resolved.
没有任何事情可以帮助我解决这个问题。 If someone can take a look and guide me would be great help.
如果有人可以看一下并指导我,那将是很大的帮助。 I would appreciate your feedback.
非常感谢您的反馈。 Also if I comment out the question part in Application.java then the survey object gets inserted in the database.
另外,如果我在Application.java中注释掉问题部分,那么调查对象将插入数据库中。 I am not sure why the questions fail and don't get insert.Please guide me.
我不确定问题为什么失败并且没有插入。请指导我。
This is my First model class: 这是我的第一堂课:
@Entity
@Table(name="question")
public class Question implements java.io.Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
@Column(name = "id")
private Long _id;
@Column(name = "label")
private String _label;
@Column(name="type")
private QuestionType _type;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="survey_id")
private Survey _survey;
public Question() {
}
public Question(final Long id, final String label, final QuestionType type, final Survey survey,final Long surveyId) {
_id = id;
_label = label;
_type = type;
_survey = survey;
Assert.notNull(_id, "_id cannot be null");
Assert.notNull(_label, "_label cannot be null");
Assert.notNull(_type, "_type cannot be null");
Assert.notNull(_survey, "_survey cannot be null");
}
public Long getId() {
return _id;
}
public void setId(Long id) {
_id = id;
}
public String getLabel() {
return _label;
}
public void setLabel(String label) {
_label = label;
}
public QuestionType getType() {
return _type;
}
public void setType(QuestionType type) {
_type = type;
}
public Survey getSurvey() {
return _survey;
}
public void setSurvey(Survey survey) {
_survey = survey;
}
@Override
public String toString() {
return "Question [_id=" + _id + ", _label=" + _label + ", _type="
+ _type + "]";
}
} }
This is my second model class: 这是我的第二堂课:
@Entity
@Table(name="survey")
public class Survey implements java.io.Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
@Column(name = "survey_id")
private Long _id;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "_survey")
private List<Question> _questions ;
@Column(name="name")
private String _name;
public Survey() {
super();
_questions = new ArrayList<Question>();
}
public Survey(Long id, List<Question> questions, String name) {
super();
_id = id;
_questions = questions;
_name = name;
Assert.notNull(_id, "_id cannot be null");
Assert.notNull(_questions, "_questions cannot be null");
Assert.notNull(_name, "_name cannot be null");
}
public Long getId() {
return _id;
}
public void setId(Long id) {
_id = id;
}
public List<Question> getQuestions() {
return _questions;
}
public void setQuestions(List<Question> questions) {
_questions = questions;
}
public String getName() {
return _name;
}
public void setName(String name) {
_name = name;
}
@Override
public String toString() {
return "Survey [_id=" + _id + ", _questions=" + _questions + ", _name="
+ _name + "]";
}
} }
This is my application class: 这是我的应用程序类:
public class Application {
public static void main(String[] args) {
System.out.println("Hibernate one to many (Annotation)");
Session session = HibernateUtil.getSessionFactory().openSession();
session.beginTransaction();
Survey survey = new Survey();
survey.setName("Ice Cream final");
session.save(survey);
Question question1 = new Question();
question1.setLabel("Whats your favorite Ice Cream");
question1.setType(QuestionType.TEXT);
question1.setSurvey(survey);
survey.getQuestions().add(question1);
session.save(question1);
session.getTransaction().commit();
System.out.println("Done");
}
Hibernate Util Class: 休眠实用程序类:
public class HibernateUtil {
private static final SessionFactory sessionFactory = buildSessionFactory();
private static SessionFactory buildSessionFactory() {
try {
// Create the SessionFactory from hibernate.cfg.xml
return new AnnotationConfiguration().configure().buildSessionFactory();
} catch (Throwable ex) {
// Make sure you log the exception, as it might be swallowed
System.err.println("Initial SessionFactory creation failed." + ex);
throw new ExceptionInInitializerError(ex);
}
}
public static SessionFactory getSessionFactory() {
return sessionFactory;
}
public static void shutdown() {
// Close caches and connection pools
getSessionFactory().close();
}
}
Hibernate config : 休眠配置:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/xxxx_survey</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.connection.password"></property>
<property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="show_sql">true</property>
<mapping class="xxxx.Survey" />
<mapping class="xxxx.Question" />
</session-factory>
</hibernate-configuration>
Pom.xml has the following dependency: Pom.xml具有以下依赖性:
<!-- MySQL database driver -->
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>5.1.6</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-annotations</artifactId>
<version>3.5.0-Final</version>
</dependency>
<dependency>
<groupId>org.slf4j</groupId>
<artifactId>slf4j-api</artifactId>
<version>1.7.5</version>
</dependency>
<dependency>
<groupId>org.slf4j</groupId>
<artifactId>slf4j-simple</artifactId>
<version>1.7.5</version>
</dependency>
<dependency>
<groupId>javassist</groupId>
<artifactId>javassist</artifactId>
<version>3.12.1.GA</version>
</dependency>
This is the error: 这是错误:
Hibernate: insert into survey (name) values (?)
Hibernate: insert into question (label, survey_id, type) values (?, ?, ?)
[main] WARN org.hibernate.util.JDBCExceptionReporter - SQL Error: 1265, SQLState: 01000
[main] ERROR org.hibernate.util.JDBCExceptionReporter - Data truncated for column 'type' at row 1
Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [xxxx.model.Question]
at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:140)
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:128)
at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66)
at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:64)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2329)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2836)
at org.hibernate.action.EntityIdentityInsertAction.execute(EntityIdentityInsertAction.java:71)
at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:268)
at org.hibernate.event.def.AbstractSaveEventListener.performSaveOrReplicate(AbstractSaveEventListener.java:321)
at org.hibernate.event.def.AbstractSaveEventListener.performSave(AbstractSaveEventListener.java:204)
at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:130)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:210)
at org.hibernate.event.def.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:56)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:195)
at org.hibernate.event.def.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:50)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:93)
at org.hibernate.impl.SessionImpl.fireSave(SessionImpl.java:705)
at org.hibernate.impl.SessionImpl.save(SessionImpl.java:693)
at org.hibernate.impl.SessionImpl.save(SessionImpl.java:689)
at xxxx.Application.main(Application.java:38)
Caused by: java.sql.SQLException: Data truncated for column 'type' at row 1
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1055)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3491)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3423)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1936)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2060)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2542)
at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1734)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2019)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1937)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1922)
at org.hibernate.id.IdentityGenerator$GetGeneratedKeysDelegate.executeAndExtract(IdentityGenerator.java:94)
at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:57)
... 16 more
You need to initialize _questions = new ArrayList<Question>();
您需要初始化
_questions = new ArrayList<Question>();
in your no arg constructor. 在您的无参数构造函数中。 You are not initializing it anywhere and trying to add a question.
您没有在任何地方初始化它并尝试添加问题。
public Survey() {
super();
_questions = new ArrayList<Question>();
}
EDIT 编辑
MySQL enum
datatype might not be well supported by hibernate. 休眠可能无法很好地支持MySQL
enum
数据类型。 Try to use a generic approach like, convert the datatype in database to either varchar
or int
and use the @Enumerated
annotation appropriately. 尝试使用通用方法,例如,将数据库中的数据类型转换为
varchar
或int
并适当使用@Enumerated
批注。
If you can not avoid using enum, then your values of the enum in database and java enum type should exactly match. 如果无法避免使用enum,则数据库中的enum值和Java enum类型应该完全匹配。
Something like, 就像是,
in db: if you have type enum('string', 'text')
. 在db中:如果您
type enum('string', 'text')
。 Your java enum should be 您的Java枚举应为
enum QuestionType {
string,
text
}
and your mapping should be @Enumerated(EnumType.STRING)
. 并且您的映射应该为
@Enumerated(EnumType.STRING)
。
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