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链接共享库与彼此共享库c ++

[英]Link shared library with each other shared libraries c++

I've successfully create my shared library, libA.so . 我已经成功创建了我的共享库libA.so。
All classes inside, have namspace common::A 里面的所有类都有namspace common :: A.

ldd libA.so
linux-vdso.so.1 =>  (0x00007fffd632d000)
libstdc++.so.6 => /usr/lib/x86_64-linux-gnu/libstdc++.so.6 (0x00007f6497d19000)
libgcc_s.so.1 => /lib/x86_64-linux-gnu/libgcc_s.so.1 (0x00007f6497b03000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f6497743000)
libm.so.6 => /lib/x86_64-linux-gnu/libm.so.6 (0x00007f6497447000)
/lib64/ld-linux-x86-64.so.2 (0x00007f6498243000)

Then, I need to create another library, B, that uses A. So I link it (-lA and -L< path_to_A >) and also compile with _I/. 然后,我需要创建另一个使用A的库B.所以我链接它(-lA和-L <path_to_A>)并使用_I /编译。 All classes inside, have namspace common::B 内部的所有类都有namspace common :: B.

Compile and make libB.so , but: 编译并生成libB.so ,但是:

1) Elipse put red X in code where I call A methods: 1) Elipse将红色X放在我称之为A方法的代码中:

 Multiple markers at this line
- Symbol '<A_method>' could not be resolved
- Function '<A_method>' could not be resolved

2) Library A seems not linked to B: 2)图书馆A似乎与B无关:

ldd libB.so
linux-vdso.so.1 =>  (0x00007fffbcbfe000)
libstdc++.so.6 => /usr/lib/x86_64-linux-gnu/libstdc++.so.6 (0x00007f695ca59000)
libgcc_s.so.1 => /lib/x86_64-linux-gnu/libgcc_s.so.1 (0x00007f695c842000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f695c483000)
libm.so.6 => /lib/x86_64-linux-gnu/libm.so.6 (0x00007f695bf7e000)
/lib64/ld-linux-x86-64.so.2 (0x00007f695d1d9000)

I can't understand why I don't have a link to A: 我不明白为什么我没有A的链接:

libA.so => .....

Any ideas? 有任何想法吗?

update 更新

This is makefile (autogenerated by eclipse): 这是makefile(由eclipse自动生成):

-include ../makefile.init

RM := rm -rf

# All of the sources participating in the build are defined here
-include sources.mk
-include src/network/mqtt/subdir.mk
-include src/data/subdir.mk
-include subdir.mk
-include objects.mk

ifneq ($(MAKECMDGOALS),clean)
ifneq ($(strip $(CC_DEPS)),)
-include $(CC_DEPS)
endif
ifneq ($(strip $(C++_DEPS)),)
-include $(C++_DEPS)
endif
ifneq ($(strip $(C_UPPER_DEPS)),)
-include $(C_UPPER_DEPS)
endif
ifneq ($(strip $(CXX_DEPS)),)
-include $(CXX_DEPS)
endif
ifneq ($(strip $(CPP_DEPS)),)
-include $(CPP_DEPS)
endif
ifneq ($(strip $(C_DEPS)),)
-include $(C_DEPS)
endif
endif

-include ../makefile.defs

# Add inputs and outputs from these tool invocations to the build variables 

# All Target
all: libB.so

# Tool invocations
libB.so: $(OBJS) $(USER_OBJS)
    @echo 'Building target: $@'
    @echo 'Invoking: GCC C++ Linker'
    g++ -L/path_where_is_A_so/ -shared -o "libB.so" $(OBJS) $(USER_OBJS) $(LIBS)
    @echo 'Finished building target: $@'
    @echo ' '

# Other Targets
clean:
    -$(RM) $(LIBRARIES)$(CC_DEPS)$(C++_DEPS)$(C_UPPER_DEPS)$(CXX_DEPS)$(OBJS)$(CPP_DEPS)$(C_DEPS) libB.so
    -@echo ' '

.PHONY: all clean dependents
.SECONDARY:

-include ../makefile.targets

If your libB doesn't use anything in libA, the linker might discard linking to libA (depending on whether the linker flag --as-needed is the default in your toolchain.) 如果你的libB没有在libA中使用任何东西,链接器可能会放弃链接到libA(取决于链接器标志--as-needed是否是工具链中的默认值。)

To force libB to link to libA, specify the flag -Wl,--no-as-needed to appear before -lA . 要强制libB链接到力霸,指定标志-Wl,--no-as-needed出庭-lA

If you are using MakeFile then do things like this: 如果您使用的是MakeFile,那么请执行以下操作:

xxxxxx_la_SOURCES = $(FILES)
xxxxxx_la_CFLAGS = $(CFLAGS)
xxxsxx_la_LDFLAGS = $(location_of_so_file)

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