java.text.ParseException：无法解析的日期“ IST 2014年9月12日23:22:46

Question

I am using jackson mapper to map the json request to an java object directly. To map the date i am using CustomDateSerializer and CustomDateDeSerializer in the getter and setter respectively.

public class CustomJsonDateSerializer extends JsonSerializer<Date> {
    @Override
    public void serialize(Date date, JsonGenerator jsonGenerator, SerializerProvider serializerProvider) throws IOException {
        SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
        String dateString = simpleDateFormat.format(date);
        jsonGenerator.writeString(dateString);
    }
}


public class CustomJsonDateDeserializer extends JsonDeserializer<Date> {
    @Override
    public Date deserialize(JsonParser jsonparser,
                            DeserializationContext deserializationcontext) throws IOException {
        SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
        String date = jsonparser.getText();
        try {
            return format.parse(date);
        } catch (ParseException e) {
            throw new RuntimeException(e);
        }
    }
}

my getter and setter in the model

@JsonSerialize(using=CustomJsonDateSerializer.class)
    public Date getBirthDate() {
        return birthDate;
    }
@JsonDeserialize(using = CustomJsonDateDeserializer.class)
public void setBirthDate(Date birthDate) {
    this.birthDate = birthDate;
}

Exception:

Could not read JSON: java.text.ParseException: Unparseable date: "Fri Sep 12 23:22:46 IST 2014" 

Can any one help me fixing this..

Answer 1

The format which you have defined is:

SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");

However it looks like the format which it is expecting is not the same( Fri Sep 12 23:22:46 IST 2014 ).

It should be like:

SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd hh:mm:ss Z yyyy",Locale.ENGLISH);

Check the Oracle docs for SimpleDateFormat

Answer 2

Change

SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");

to

SimpleDateFormat dF=new SimpleDateFormat("EEE MMM dd hh:mm:ss z yyyy",Locale.ENGLISH);

Answer 3

更改日期格式可以解决问题-“ EEE MMM dd HH：mm：ss Z yyyy”