Shell脚本中的MySQL数组（Linux）

Question

I am trying to read out ids from mysql and then delete the entry with id-1.

today_time=$(date -d "now" '+%d-%b-%Y %H:%M:%S')  
query_find_id="SELECT id FROM guestlist WHERE value <= '$today_time'"

array_query=$(mysql -u $USER -p$PASSWORD $TABLE_NAME -e "$query_find_id")

array_id=($(for i in $array_query; do echo $i; done))

for j in "${array_id[@]}"; k=$j-1; mysql -u $USER -p$PASSWORD $TABLE_NAME -e "DELETE FROM guestlist WHERE id = '$k'"; done

The array is empty every time. What am I doing wrong?

Answer 1

如果您的value today_time DATETIME，则today_time的日期格式应为%Y-%m-%d %H:%M:%S 。