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Mysql查询Join两个表

[英]Mysql query to Join two tables

I am writing a simple chat service.我正在编写一个简单的聊天服务。 I want to pick out a messages thread between two people only a sender and a recipient using either their usernames or user ids.我想选择两个人之间的消息线程,只有发件人和收件人使用他们的用户名或用户 ID。 I have my query below.我在下面有我的查询。 It has a slight problem, is returning a message twice.它有一个小问题,正在返回一条消息两次。 How can I fix this?我怎样才能解决这个问题?

For example if my sender has the uid '101' and my recipient has the username 'janed', my query is例如,如果我的发件人有 uid '101' 而我的收件人有用户名 'janed',我的查询是

SELECT * FROM chat LEFT JOIN users ON sender=uid OR receiver=uid  WHERE username='janed' OR (sender='101' AND receiver='janed') OR (sender='janed' AND receiver='101') ORDER BY msg_id ASC

Users table用户表

---------------------------------
uid |fname  |mname  |username   |
---------------------------------
101 |John   |Doe    |jdoe       |
---------------------------------
102 |Jane   |Doe    |janed      |
---------------------------------
103 |Ann    |Other  |aother     |
---------------------------------

Chat table聊天桌

---------------------------------------------
msg_id  |sender |receiver   |content        |
---------------------------------------------
1       |101    |102        | Hello Jane    |
---------------------------------------------
2       |102    |101        | Hello John    |
---------------------------------------------
3       |103    |101        | Hi John       |
---------------------------------------------

Add a GROUP BY clause添加GROUP BY子句

SELECT 
    *
FROM
    chat
        LEFT JOIN
    users ON sender = uid OR receiver = uid
WHERE
    username = 'janed'
        OR (sender = '101' AND receiver = 'janed')
        OR (sender = 'janed' AND receiver = '101')
GROUP BY msg_id
ORDER BY msg_id ASC
SELECT
    u.*, c.*
  FROM Users u
  LEFT JOIN Chat c ON (
    c.sender = u.uid OR c.receiver = u.uid
  )
  WHERE u.uid = 101 OR u.uid = 102 /* and/or other conditions */
  GROUP BY c.msg_id
  ORDER BY c.msg_id ASC

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