用正则表达式分割复杂的字符串

Question

I have very basic knowledge of regular expressions and this one is just too hard for me. I need to split string into three parts.

My input looks like this XXX YYY:ZZZ: (always ends with :ZZZ: )

• XXX can be anything including $&+,:;=?@#|'<>.-^*()%! and spaces
• YYY are alphabetical chars which can end with . or are not there at all
• ZZZ is number which can have leading zeroes and is in between two : at the end of string

Trickiest string I can come up with is Lo-rem ip sum.,::0001678154: . ZZZ would be 0001678154 we can get rid off :ZZZ: so remaining part is Lo-rem ip sum.,: but last char is not either alphanumeric or . so that means YYY is not included in this string XXX is whatever remained ( Lo-rem ip sum.,: )

Now I have horrible half functioning code with hardcoded lengths, ifs, substrings and splits I believe you could come up with better solution. Thanks

Answer 1

The below regex would capture and store the three set of characters into three separate groups,

^(?<xxx>.*?)(?<yyy>(?:[A-Za-z0-9])+\.?)?:(?<zzz>\d+):$

DEMO

? after the second group will make the group as optional.