简体   繁体   English

无法获取scanf_s或切换正常工作

[英]Can't get scanf_s or switch working

I'm having some problems with the scanf_s(); 我在scanf_s()中遇到了一些问题; function or the switch function, the first time I run my code it doesn't recognize the correct char and loops back to the beginning, but after that it works just fine. 函数或切换函数,当我第一次运行代码时,它无法识别正确的字符并循环回到开头,但是之后就可以正常工作了。 It is a simple calculator. 这是一个简单的计算器。

There probably is some easy solution to this since I have just started learning programming, but I can't find it. 由于我刚刚开始学习编程,因此可能有一些简单的解决方案,但找不到。

All the text is in Finnish, but I hope the code itself is understandable. 所有文字均为芬兰语,但我希望代码本身可以理解。

All feedback is welcome since I am eager to learn what I should and shouldn't do. 欢迎大家提供所有反馈,因为我渴望学习应该做和不应该做的事情。

#include <stdio.h>
#include <stdlib.h>

float luku1 = 0;
float luku2 = 0;
float tulos = 0;
char valinta = '\0';

int main()
{
    system("cls");
    printf("Minkä laskusuorituksen haluaisit tehdä? (+,-,*,/)\n");
    fflush(stdin);
    scanf_s("%c", &valinta);
    switch (valinta){
    case '+':
        printf("Anna yhteenlaskettavat luvut.\n>");
        scanf_s("%f %f", &luku1, &luku2);
        tulos = luku1 + luku2;
        printf("Lukujen summa on %4.2f\n", tulos);
        break;
    case '-':
        printf("Anna vähennettävät luvut.\n>");
        scanf_s("%f %f", &luku1, &luku2);
        tulos = luku1 - luku2;
        printf("Lukujen summa on %4.2f\n", tulos);
        break;
    case '*':
        printf("Anna kerrottavat luvut.\n>");
        scanf_s("%f %f", &luku1, &luku2);
        tulos = luku1 * luku2;
        printf("Lukujen tulo on %4.2f\n", tulos);
        break;
    case '/':
        printf("Anna jaettavat luvut.\n>");
        scanf_s("%f %f", &luku1, &luku2);
        if (luku2 == 0)
        {
            printf("Nollalla ei voida jakaa.\n");
            system("pause");
            main();
        }
        else
        {
            tulos = luku1 / luku2;
            printf("Lukujen jako on %4.2f\n", tulos);
        }
        break;
    default:
        printf("En tunnistanut laskutoimitusta, yritä uudelleen.\n");
        system("pause");
        main();
        break;
    }
}

scanf_s("%c", &valinta); need another parameter. 需要另一个参数。 @mafso @mafso

 scanf_s(" %c", &valinta, 1);

Adding a space before "%c" will help should code call scanf_s(" %c", &valinta); 在代码"%c"之前添加一个空格将有助于scanf_s(" %c", &valinta); again. 再次。

"The fscanf_s function is equivalent to fscanf except that the c , s, and [ conversion specifiers apply to a pair of arguments (unless assignment suppression is indicated by a *). The first of these arguments is the same as for fscanf. That argument is immediately followed in the argument list by the second argument, which has type rsize_t and gives the number of elements in the array pointed to by the first argument of the pair." “ fscanf_s函数等效于fscanf,不同之处在于c ,s和[转换说明符适用于一对参数(除非分配抑制用*表示)。这些参数中的第一个与fscanf相同。该参数在参数列表中紧随其后的是第二个参数,其类型为rsize_t,并给出该对中第一个参数所指向的数组中的元素数。”

C11dr §K.3.5.3.2 4 C11dr§K.3.5.3.24


Recommend dropping fflush(stdin); 推荐fflush(stdin); as it is non-portable and may/may not work as expected. 因为它是不可携带的,并且可能/可能无法按预期工作。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM