如何减小float-python的大小

Question

I am trying to create a readable file name generator given the number of bytes, but also doing it without if statements or loops:

def memory_size(n):
     suffix = ['B','KB','MB','GB','TB']
     return ('%.1f'+suffix[int(math.log10(n)/3)]) %(n/?)

I am stumped as to what i can divide 'n' by so that it will show the user the decreased file size without using an if statement or a loop?

Answer 1

1024**(math.log10(n)/3)

The stupid thing about not using for loops is you're gonna get annoying float division errors

>>> mem(1000000)
'1.0MB'
>>> mem(1000000000)
'0.9GB'

I'd put a call to round() in your code