正则表达式，在python中使用搜索

Question

I want to decode a some hex in python.

In part of the string \\xcd\\xed\\xb0\\xb2

    text = re.search(r'(\\x\w{2}){4}', rtf)

    unicodeText = text.decode('gb2312')

Error: '_sre.SRE_Match' object has no attribute 'decode'

Hope someone can help, Thanks

Answer 1

re.search returns a Match object , not a matched string.

Use group method to get the matched string.

>>> rtf = r'\xcd\xed\xb0\xb2'
>>> matched = re.search(r'(\\x\w{2}){4}', rtf)
>>> text = matched.group()
>>> text.decode('string-escape').decode('gb2312')
u'\u665a\u5b89'

# In Python 3.x
# >>> text.encode().decode('unicode-escape').encode('latin1').decode('gb2312')
# '晚安'

---

BTW, you don't need to use regular expression, what you want is convert \\xOO :

Python 2.x:

>>> rtf = r'\xcd\xed\xb0\xb2'
>>> rtf.decode('string-escape').decode('gb2312')
u'\u665a\u5b89'
>>> print rtf.decode('string-escape').decode('gb2312')
晚安

Python 3.x:

>>> rtf = r'\xcd\xed\xb0\xb2'
>>> rtf.encode().decode('unicode-escape').encode('latin1').decode('gb2312')
'晚安'