c - *（void **）＆（int [2]）{0，PAGE_SIZE}; 含义？

Question

Context

Reading some kernel code.

Problem

I cannot get my head on what this line is meaning

*(void **) &(int[2]){0,PAGE_SIZE};

and more, what does this means

{0,PAGE_SIZE}

To me it doesn't look like a function with that comma.

What could be going on with this code ? I don't understand the indirections here.

Is it a function or a cast ? What does the bracket part means ? Seems so convoluted to me but definitely has a meaning.

Answer 1

(int[2]) { 0, PAGE_SIZE }

is an expression (called compound literal ) whose value is an array of two int s. The address of this array is taken, casted to void ** , and dereferenced.

The net result is a reinterpretation of the array contents as a pointer to void.

Note that you can take the address of a compound literal, as they are lvalues. See eg. this question .