[英]Regex to match 2 or more commas
I'm trying to write a regex that will identify whether a string has 2 or more consecutive commas. 我正在尝试编写一个正则表达式,用于识别字符串是否包含2个或更多连续逗号。 For example: 例如:
hello,,457
,,,,,
dog,,,elephant,,,,,
Can anyone help on what a valid regex would be? 任何人都可以帮助有效的正则表达式吗?
String str ="hello,,,457";
Pattern pat = Pattern.compile("[,]{2,}");
Matcher matcher = pat.matcher(str);
if(matcher.find()){
System.out.println("contains 2 or more commas");
}
The below regex would matches the strings which has two or more consecutive commas, 以下正则表达式将匹配具有两个或更多连续逗号的字符串,
^.*?,,+.*$
You don't need to include start and the end anchors while using the regex with matches
method. 使用带有matches
方法的正则表达式时,您不需要包含开始和结束锚点。
System.out.println("dog,,,elephant,,,,,".matches(".*?,,+.*"));
Output: 输出:
true
Try: 尝试:
int occurance = StringUtils.countOccurrencesOf("dog,,,elephant,,,,,", ",,");
or 要么
int count = StringUtils.countMatches("dog,,,elephant,,,,,", ",,");
depend which library you use: Check the solution here: Java: How do I count the number of occurrences of a char in a String? 取决于您使用的库:在此处检查解决方案: Java:如何计算String中char的出现次数?
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