将多参数匿名函数作为参数的Scala函数

Question

I have a function named sum that can take a single parameter anonymous function as a parameter, and two Integers.

def sum (f: Int => Int , a: Int, b: Int): Int =
{
  if(a > b) 0 else f(a) + sum(f, a + 1, b)
}
  sum((x: Int) => x , 2, 10)

How could I modify the function definition so that it can take a multiple parameter function, so I could call it like this:

sum((y: Int, i: Int) => y + i => x , 2, 10)

I know the function I have supplied would be pretty useless when passed a multiple parameter function.. but I am just looking for how it can be done..

Thanks

Answer 1

As simple as this:

def sum (f: (Int, Int) => Int , a: Int, b: Int): Int = ???

Or a curried version:

def sum (f: Int => Int => Int , a: Int, b: Int): Int = ???

Although you can curry any function just calling f.curried