[英]Joining two tables SQL
I have a question. 我有个问题。 I have two tables employees and salary and I want to display the full name and salary grade of all employee who's grade_ID is 2 or 3 sort by employee_ID.
我有两个表employee和salary,我想显示所有grade_ID为2或3(按employee_ID排序)的雇员的全名和薪水等级。
Here are the tables: 表格如下:
Salary_ID LOW_SALARY High Salary
1 1 250000
2 250001 500000
3 500001 750000
4 750001 999999
EMPLOYEE_ID FIRST_NAME Last_NAME Salary
1 James Smith 800000
22 Roy Red 375000
2 Ron Johnson 550000
5 Rob Green 225000
I know I have to join the tables, this is what I have so far: 我知道我必须加入表格,这是我到目前为止的结果:
SELECT employees2.FIRST_NAME,
employees2.last_name,
salary_grades.SALARY_GRADE_ID,
employees2.SALARY
FROM employees2,
salary_grades
ORDER BY employees2.EMPLOYEE_ID;
what do i do next? 我下一步该怎么办? I am stuck.
我被困住了。 Can anyone help me out?
谁能帮我吗? Thank you.
谢谢。
It may be the query you're looking for: 它可能是您要查找的查询:
SELECT E.EMPLOYEE_ID
,E.FIRST_NAME
,E.LAST_NAME
,E.SALARY
FROM employees E
INNER JOIN salary S ON S.LOW_SALARY <= E.SALARY
AND S.HIGH_SALARY >= E.SALARY
AND S.SALARY_ID IN (2,3)
ORDER BY E.EMPLOYEE_ID
Hope this will help you. 希望这会帮助你。
Simply have to use a join condition that compares the employee salary with the low and high limits of the salary rank, ie 只需使用将员工薪水与薪资等级的上下限进行比较的加入条件,即
SELECT E.*, S.* FROM Employee AS E
INNER JOIN dbo.Salary AS S
ON S.LOW_SALARY <= E.Salary AND S.High_Salary >= E.Salary
If you want, you can filter by Salary_Id
between 2 and 3 如果需要,可以按
Salary_Id
在2到3之间进行过滤
NOTE: This syntax should work in the 3 types of servers. 注意:此语法应在3种类型的服务器中工作。
Test data, for SQL Server: 针对SQL Server的测试数据:
CREATE TABLE Salary (Salary_Id INT, LOW_SALARY INT, High_Salary INT)
INSERT INTO Salary VALUES(1,1,250000)
INSERT INTO Salary VALUES(2,250001,500000)
INSERT INTO Salary VALUES(3,500001,750000)
INSERT INTO Salary VALUES(4,750001,999999)
CREATE TABLE Employee (Employee_Id INT, FIRST_NAME varchar(50), Last_NAME varchar(50), Salary INT)
INSERT INTO Employee VALUES(1, 'James', 'Smith', 800000)
I'll give the SQL Server (2008+) answer. 我将给出SQL Server(2008+)的答案。
SELECT E.FIRST_NAME, E.last_name, S.SALARY_GRADE_ID, E.SALARY
FROM employees2 E
JOIN salary_grades S ON (E.SALARY BETWEEN S.LOW_SALARY AND S.HIGH_SALARY) AND S.SALARY_ID IN (2, 3)
ORDER BY E.EMPLOYEE_ID;
SELECT employees2.FIRST_NAME, employees2.LAST_NAME, employees2.SALARY, salary_grades.SALARY_GRADE_ID
FROM employees2, salary_grades
WHERE employees2.SALARY BETWEEN salary_grades.LOW_SALARY AND salary_grades.HIGH_SALARY
ORDER BY salary_grades.SALARY_GRADE_ID
So I tried using this script, it works but do i use IN to display the range of 2 and 3 in sqldeveloper? 所以我尝试使用此脚本,它可以工作,但是我是否使用IN在sqldeveloper中显示2和3的范围?
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