仅在文件路径具有特定扩展名时显示数组行

Question

I have an array, which contains amongst other things a file path to a video file. There are various file formats .avi, .mp4 etc etc.

Now I only want to display the rows where the file path's file extension is .mp4.

Currently I'm using a function to extract the file extension, but I'm having trouble doing this on the fly while displaying the rows.

An example of the file path: c:\\TempVideoDir\\Office-P-cam01-20140826-083016.avi

The function im using to get the file ext:

function get_fileext($filename) {

   $cut_fileext = (explode('.', $filename));
   $just_fileext = $cut_fileext[1];

   echo $just_fileext; 
}

Which works fine.

Now I'm querying the database to get the filepath along with other details about the file, and I only want to display the rows where the file path contains a .mp4 file.

I've tried everything I could thing of/find on Google etc but this is what I currently have:

  $stmt->execute();
  $result = $stmt->fetchAll();

  foreach($result as $row) {

        if (in_array((get_fileext($row["Filename"])== "mp4"), $result)) {

        echo "  blah blah

I dont have the option of adding the file extension into the database table as this is backed up automatically by a piece of equipment.

So, whadoyareckon? is it possible to do it on the fly like this?

Any help is much appreciated!

Thanks

Answer 1

I dont think you can use in_array() like that. Its searching the entire index of the array, so when it looks ate $result[] its never going to find $row['filename'] with only an ext.

try this:

//looping through $result array
foreach($result as $row) {

    //check if $row['filename'] has a string with a mp4 extension.
    if (get_fileext($row["Filename"])== "mp4") {

    echo "Row has a filename with the mp4 extension';

also as someone else pointed out fix your get_fileext() method to return something.

function get_fileext($filename) {

   $cut_fileext = (explode('.', $filename));
   $just_fileext = $cut_fileext[1];

   return $just_fileext; 
}

Answer 2

Your function isn't returning a value. It's emitting the value to the output:

function get_fileext($filename) {

    $cut_fileext = (explode('.', $filename));
    $just_fileext = $cut_fileext[1];

    echo $just_fileext; 
}

So there's no way for anything invoking that function to see that result. Instead, return the value:

function get_fileext($filename) {

    $cut_fileext = (explode('.', $filename));
    $just_fileext = $cut_fileext[1];

    return $just_fileext; 
}

That way the invocation of the function itself evaluates to the returned value, allowing you to use the function in your logic.

Answer 3

You could consider adjusting your database query to only return rows with ".mp4" files.

Change your query to have something like:

filepath = "%.mp4"

In MySQL the % operator is a wildcard, so this will match any strings ending in ".mp4"