当具有特定数量的细分时，将正则表达式模式匹配到URL

Question

I have urls like these:

example.com/test/testurl
example.com/test/test-url
example.com/test/testurl/content
example.com/test/test-url/content

I'm working on a redirect in here so, I need a regex to match the url when it has only 2 segments (like the 2 first ones) getting the second segment in a group, but to fail in all the others.

Here's the pattern I accomplished so far:

test\/(\w+)(?!\/)\b

This one matches the first url and fails on the third, great.

But it ends up matching the second and fourth url, capturing the word up to the dash. I'm pulling my hair out on this one, any pointers are appreciated. Thanks in advance ! :)

Answer 1

Use this regex instead:

test/([^/]+)

It will capture everything that is not a slash after test/ .

Escape the slashes appropriately if needed.

Answer 2

First throw out \\b . That's to match word boundaries and URLs can contain non-word characters.

I'm going to make the assumption that you're getting the url in its own string without any other accompanying text.

That being the case the following regex will:

• match the start of a string
• match one or more characters up to the first forward slash
• match /test/
• match one or more characters up to another slash
• optionally match a slash
• match the end of a string

REGEX

^[^/]+/test/[^/]+/?$

REY

NO MATCH: example.com/test/
MATCH: example.com/test/testurl
MATCH: example.com/test/test-url
MATCH: example.com/test/test-url/
NO MATCH: example.com/test/testurl/content
NO MATCH: example.com/test/test-url/content

Also if you need to add the protocol, you can rewrite the regex thusly:

^[^:]+://[^/]+/test/[^/]+/?$

Answer 3

^(?=[^\/]*\/[^\/]*\/[^\/]*$).*

Try this. This will match only if url has 2 segments. See demo.

http://regex101.com/r/gG5fF6/3