[英]Eclipselink JPA ManyToOne mapping issue
Am new to JPA(eclipselink), am trying to use ManyToOne unidirectional mapping
, i have superclass Student
and subclass Book
, when i try to save the object i end up with exceptions, the details are given below我是 JPA(
ManyToOne unidirectional mapping
,我正在尝试使用ManyToOne unidirectional mapping
,我有superclass Student
和subclass Book
,当我尝试保存对象时,我最终遇到了异常,详细信息如下
Student is the Parent Class学生是家长班
@Entity
@Table(name="STUDENT")
@TableGenerator(name="student_s", initialValue=1)
public class Student {
@Id
@Column(name="student_id")
@GeneratedValue(strategy=GenerationType.TABLE ,generator="student_s")
private int studentID;
@Column(name="full_name",nullable=false)
private String student_name;
public int getStudentID() {
return studentID;
}
public void setStudentID(int studentID) {
this.studentID = studentID;
}
public String getStudent_name() {
return student_name;
}
public void setStudent_name(String student_name) {
this.student_name = student_name;
}
}
Book is the Child Class书是儿童班
@Entity
@Table(name="BOOK")
@TableGenerator(name="book_s", initialValue=1)
public class Book {
@Id
@Column(name="book_id")
@GeneratedValue(strategy=GenerationType.TABLE ,generator="book_s")
private int bookID;
@Column(name="book_name")
private String bookName;
@Column(name="student_id")
private String studentID;
@ManyToOne(cascade=CascadeType.ALL)
@JoinColumn(name="student_id",referencedColumnName="student_id",insertable=false,updatable=false)
private Student student;
public int getBookID() {
return bookID;
}
public void setBookID(int bookID) {
this.bookID = bookID;
}
public String getBookName() {
return bookName;
}
public void setBookName(String bookName) {
this.bookName = bookName;
}
public String getStudentID() {
return studentID;
}
public void setStudentID(String studentID) {
this.studentID = studentID;
}
public Student getStudent() {
return student;
}
public void setStudent(Student student) {
this.student = student;
}
}
Main Class which executes the persist operation, while performing persist the unknown column exception is thrown.执行持久化操作的主类,在执行持久化时抛出未知列异常。
public class Main {
public static void main(String args[]){
Student student = new Student();
student.setStudent_name("Prem");
Book book = new Book();
book.setBookName("The Best Laid Plan");
book.setStudent(student);
EntityManagerFactory emf=Persistence.createEntityManagerFactory("premjpaeclipselink");
EntityManager em = emf.createEntityManager();
em.getTransaction().begin();
em.persist(book);
em.getTransaction().commit();
em.close();
emf.close();
}
}
Exception:例外:
]: sql: Connection(635083092)--INSERT INTO BOOK (book_id, book_name, student_id) VALUES (?, ?, ?)
bind => [351, The Best Laid Plan, null]
[EL Fine]: sql: SELECT 1
[EL Warning]: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'book_name' in 'field list'
Error Code: 1054
Call: INSERT INTO BOOK (book_id, book_name, student_id) VALUES (?, ?, ?)
bind => [351, The Best Laid Plan, null]
Exception in thread "main" javax.persistence.RollbackException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'book_name' in 'field list'
Error Code: 1054
Call: INSERT INTO BOOK (book_id, book_name, student_id) VALUES (?, ?, ?)
bind => [351, The Best Laid Plan, null]
at org.eclipse.persistence.internal.jpa.transaction.EntityTransactionImpl.commit(EntityTransactionImpl.java:157)
at org.prem.jpa.eclipselink.Main.main(Main.java:31)
Caused by: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'book_name' in 'field list'
Error Code: 1054
Call: INSERT INTO BOOK (book_id, book_name, student_id) VALUES (?, ?, ?)
bind => [351, The Best Laid Plan, null]
at org.eclipse.persistence.exceptions.DatabaseException.sqlException(DatabaseException.java:331)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:900)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeNoSelect(DatabaseAccessor.java:962)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.basicExecuteCall(DatabaseAccessor.java:631)
at org.eclipse.persistence.internal.databaseaccess.ParameterizedSQLBatchWritingMechanism.executeBatch(ParameterizedSQLBatchWritingMechanism.java:149)
at org.eclipse.persistence.internal.databaseaccess.ParameterizedSQLBatchWritingMechanism.executeBatchedStatements(ParameterizedSQLBatchWritingMechanism.java:134)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.writesCompleted(DatabaseAccessor.java:1836)
at org.eclipse.persistence.internal.sessions.AbstractSession.writesCompleted(AbstractSession.java:4244)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.writesCompleted(UnitOfWorkImpl.java:5594)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.acquireWriteLocks(UnitOfWorkImpl.java:1646)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitTransactionAfterWriteChanges(UnitOfWorkImpl.java:1614)
at org.eclipse.persistence.internal.sessions.RepeatableWriteUnitOfWork.commitRootUnitOfWork(RepeatableWriteUnitOfWork.java:284)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitAndResume(UnitOfWorkImpl.java:1169)
at org.eclipse.persistence.internal.jpa.transaction.EntityTransactionImpl.commit(EntityTransactionImpl.java:132)
... 1 more
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'book_name' in 'field list'
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
at com.mysql.jdbc.Util.getInstance(Util.java:386)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1053)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4096)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4028)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2490)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2651)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2734)
at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2155)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2458)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2375)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2359)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeDirectNoSelect(DatabaseAccessor.java:890)
... 13 more
I can see this line from your exception stacktrace:我可以从您的异常堆栈跟踪中看到这一行:
Unknown column 'book_name' in 'field list
' Unknown column 'book_name' in 'field list
”中的Unknown column 'book_name' in 'field list
”
make sure column "book_name" in BOOK table is correct in database确保 BOOK 表中的列“book_name”在数据库中是正确的
i hope it helps !!!我希望它有帮助!!!
Change private String studentID;
更改
private String studentID;
in Book class to private int studentID;
在 Book 类到
private int studentID;
and also change respective getter and setter.并更改各自的 getter 和 setter。
Entity works well.实体运作良好。 It is the problem of column name.
是列名的问题。 To make sure your DDL, you can use with
为了确保您的 DDL,您可以使用
<property name="eclipselink.ddl-generation" value="drop-and-create-tables"/>
. <property name="eclipselink.ddl-generation" value="drop-and-create-tables"/>
。
As @Sanket Pipariya said, you don't need正如@Sanket Pipariya 所说,你不需要
@Column(name="student_id")
private String studentID;
Because you already have Student Object ('student_id' column in Book table).因为您已经有了 Student 对象(Book 表中的“student_id”列)。 You are using
insertable=false
in Student attribute in Book Class so that when you persist Book object along with Student attribute, student_id
column in Book table will be null.您在 Book Class 的 Student 属性中使用
insertable=false
,以便当您将 Book 对象与 Student 属性一起持久化时,Book 表中的student_id
列将为空。
This exception will be removed when you create table in database of both book and student.当您在 book 和 student 的数据库中创建表时,将删除此异常。 Then the records will be inserted.
然后将插入记录。
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