Hibernate HQL出错 - 意外令牌：

Question

***import org.hibernate.Query;***

String hql = "FROM :className WHERE userCreate like ':userName'";
Query query = session.createQuery(hql);
query.setParameter("className", className);
query.setParameter("userName", userName);
List<Node> result = query.list();

And have an error

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: : near line 1, column 6 [FROM :className WHERE userCreate like ':userName']
at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91)
at org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.parse(QueryTranslatorImpl.java:304)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:203)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:126)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:88)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:167)
at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301)
at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236)
at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1800)
at com.SDC.DAO.DAOFileAndFolderService.findUserCreteFileOrFolder(DAOFileAndFolderService.java:36)
at com.SDC.View.Main.main(Main.java:57)

Exception in thread "main" java.lang.NullPointerException at com.SDC.View.Main.main(Main.java:58)

Answer 1

You cannot use named parameters for Hibernate queries. You can get around this by manually appending the name of the table into your hql string. Your code would look instead like this:

String hql = "FROM " + className + " WHERE userCreate like ':userName'";
Query query = session.createQuery(hql);
query.setParameter("userName", userName);
List<Node> result = query.list();