查找正则表达式以返回单个组中的所有特殊字符

Question

I want the regex to return all special characters in a single group. I have made the regex that would return the characters using [^a-zA_Z0-9] but this one does not return the characters not being a letter or digit in a single group.

For example if the string to be checked is Today is ~Friday() then I am expecting that the output would be ~() in one string so that I can replace them in one go.

But using the regex I provided I am getting:

0: [14,15] ~
0: [21,22] (
0: [22,23] )

Answer 1

Try using replaceAll method.

Below you have code that find all fragments matching to normal character sequence and replaces that sequence with empty string.

    String in = "Today is ~Friday()";
    String out = in.replaceAll("[a-zA-Z0-9 ]+", "");

    System.out.println(out);

And the result is:

~()