分配的参数和定义函数，jQuery

Question

Right now I have the code:

$.get("test.php", function(($cars){
    $cars = cars;
}, "json");

$(function(cars){
    $.each(cars, function(i, startList){
        if(iNLarr[i]){
            iNLarr[i](startList.name);
        }
    });
});

Ok I'm assigning the $cars array to the cars variable. Basically $cars is an array of objects, each object is an associative array. I need to be able to work on the array so I assigned it to the variable first. The next function uses the information in cars and displays it in html elements. iNLarr is an array of functions each function changing a replacing name html elements with the name retrieved from the $cars array of objects.

Whenever I run the function I get something back like array.prototype.map is not a valid parameter. I am thinking that startList is a made up parameter that I was hoping would be assigned to the objects so I could retrieve each name, but I'm guessing that's not the case, can anyone help me.

I'm alos not sure I've defined the function properly.

Answer 1

Use the below code to accomplish your task :

$.get("test.php", function(($cars){
    cars = $cars;
    $.each(cars, function(i, startList){
        if(iNLarr[i]){
            iNLarr[i](startList.name);
        }
    });
}, "json");

Tell me if need any explanation.

Answer 2

At the moment neither function makes sense. This line in the first:

$cars = cars;

will overwrite the result of your ajax call with an undefined (at least, undefined in the code shown) variable cars . And then you don't actually do anything further with $cars - no point giving it a value if you don't use it.

Then your second function is getting bound as a document ready handler which means the cars argument will be set to reference jQuery . That is, when you call $() or jQuery() and pass a function as an argument:

$(function() { /* some code */ });

...that function will be called when the DOM is ready.

You should do all of the processing you need with your ajax call within the first function, something like this:

$.get("test.php", function(cars){
    $.each(cars, function(i, startList){
        if(iNLarr[i]){
            iNLarr[i](startList.name);
        }
    });
}, "json");

You may need to wrap the above in a document ready handler, or put it in a script at the end of the body.

Answer 3

The $(function () { … } notation is for executing code at document ready/load time.

Your $.get is done at script loading time (begore document loaded), but the response can come after the document loading.

$(function() {
    $.get("test.php", function(cars) {
        $.each(cars, function(i, startList) {
            if(iNLarr[i]){
                iNLarr[i](startList.name);
            }
        });
    }, "json");
});

May it help you.