如何解析此unicode字符串列表

Question

I wan to parser this unicode string list into a table:

[u'$760,507,625 (USA) (18 November 2010)', u'$760,505,847 (USA) (14 November 2010)', u'$760,462,559 (USA) (7 November 2010)', u'$760,410,799 (USA) (31 October 2010)',

So the result I want is:

[[760507625, 11, 18, 2010, 'USA'], 
 [760505847, 11, 7, 2010, 'USA'],
  ....
]

As you can see, the format will be [money, month, day, year, country]

Maybe you can provide me the tools which can handle this problem. Am I making me clear? Thanks so much!

Answer 1

The usual way I would handle this would be with a regular expression to grab the fields out of each line, then a line or two for each field to convert it to the desired format. This isn't foolproof—it'll crash if a line has an entry with a mis-spelled month, for example—but it's enough for most ad-hoc tasks.

#!/usr/bin/env python2.7

import re

data = [u'$760,507,625 (USA) (18 November 2010)',
        u'$760,505,847 (USA) (14 November 2010)',
        u'$760,462,559 (USA) (7 November 2010)',
        u'$760,410,799 (USA) (31 October 2010)',
       'blah']

RE_DATA = re.compile(r'^\$([0-9,]+) \(([A-Z]+)\) \(([0-9]+) ([A-Za-z]+) ([0-9]+)\)$')

MONTHS = {
    'January': 1,
    'February': 2,
    'March': 3,
    'April': 4,
    'May': 5,
    'June': 6,
    'July': 7,
    'August': 8,
    'September': 9,
    'October': 10,
    'November': 11,
    'December': 12
}

for entry in data:
    match = RE_DATA.match(entry)
    if match is None:
        print 'Error! %r did not match pattern' % entry
        continue

    amount, country, day, month, year = match.groups()
    amount = int(amount.replace(',', ''))
    country = str(country)
    day = int(day)
    month = MONTHS[month]
    year = int(year)

    print [amount, month, day, year, country]

Prints:

[760507625, 11, 18, 2010, 'USA']
[760505847, 11, 14, 2010, 'USA']
[760462559, 11, 7, 2010, 'USA']
[760410799, 10, 31, 2010, 'USA']
Error! 'blah' did not match pattern