如何使用正则表达式获得[0]的最后一次出现？

Question

I'm trying to get the last occurrence of a situation.

obj.foo[0].bar[0].name

I try this code but just got the first [0] and if I put $ at end just doesn't work.

\[(\d+)\](?:(?!\[\d+\]))

Answer 1

You have to assert that another same group cannot be somewhere after the match, not just immediately after. See this modification:

\[(\d+)\](?!.*?\[\d+\])
            ^^^

Or you can switch to a backtracking approach:

.*\[(\d+)\]

Here is a regex demo for the first regex, and here is one for the other.

Answer 2

Depending if you want the brackets included, you could use the following:

var r = s.match(/\[\d+\]/g)[1]

If you do not want the delimiters you can slice them from the group index.

var r = s.match(/\[\d+\]/g)[1].slice(1,-1)