按日期分组（php，mysql）

Question

I have a mysql table

daten    name      sub   rate
*******************************
09.22  Jonh     some5      one
09.22  Jonh     some2      two
09.22  Jonh     some3      two

Need to get in html:

Jonh:
date some5 some2 some3
***********************
09.22 one  two   two

I do:

$str = "SELECT * FROM table WHERE name= '$name' group by daten";
$rts = mysql_query($str);

echo "<h1>".$name."</h1>";
echo "<table border=\"1\"><th>date</th> "; 

   while($row = mysql_fetch_array($rs)) {

echo  "<th>".$row['sub'] . "</th></tr>";
echo  "<tr><td>".$row['daten'] ."</td><td>".$row['rate']."</td></tr>";
     }
echo "</table>";

But such a code, when group by daten, displays only the first value. Without group all quite wrong.

Please tell me what is wrong and where to dig.

Thank you

Answer 1

you need to get all data in single row so you have to use if condition under your query. Mysql if function returns a value based on a condition. The syntex of IF is

if (expr, if_true_expr, if_false_expr)

If the expr evaluates to TRUE ie, expr is not NULL and expr is not 0, the IF function returns the if_true_expr, otherwise it returns if_false_expr. The IF function return a numeric or a string, depending on how it is used.

SELECT
    `name`
  , MAX(IF(`rate` = 'one', `rate`, NULL)) some5
  , MAX(IF(`rate` = 'two', `rate`, NULL)) some2
  , MAX(IF(`rate` = 'two', `rate`, NULL)) some3
FROM
  database1
GROUP BY
  name;

Answer 2

use this query : SELECT daten, GROUP_CONCAT(sub) as sub FROM table WHERE name= '$name' group by daten. you will get expected output.