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在Django管理表单中按用户过滤ModelChoiceField

[英]Filter ModelChoiceField by User in Django Admin Form

I'm new in Django and I have created a project with this structure: 我是Django的新手,并且创建了一个具有以下结构的项目:

model.py model.py

from django.contrib.auth.models import User, Group

class MyModel(models.Model):
    created = models.DateTimeField(auto_now_add=True)
    created_by = models.ForeignKey(User, null=True, blank=True)
    group = models.ForeignKey(Group, null=True, blank=True)
    ...
    ...

admin.py admin.py

class MyModelAdmin(admin.ModelAdmin):
    form = MyModelForm
    ...

    def queryset(self, request):
        qs = super(MyModelAdmin, self).queryset(request)
        # If super-user, show all records
        if request.user.is_superuser:
            return qs
        # If user have group, show all records of the group
        if request.user.groups.all().count() > 0:
            return qs.filter(group=(request.user.groups.all()))
        #Show only the records that the user have been created
        return qs.filter(created_by=request.user)

I want to show only the records that are assigned to a specific Group. 我只想显示分配给特定组的记录。 It´s ok, but how could I create the same filter that I use in admin.py to filter the choices by user´s group in my Django form? 可以,但是如何创建与admin.py使用的过滤器相同的过滤器,以按Django表单中的用户组过滤选择? How could I pass the actual user that is logging to a ModelForm class? 如何传递登录到ModelForm类的实际用户?

Forms.py Forms.py

class MyModelForm(forms.ModelForm):
    group = forms.ModelChoiceField(Group.objects.filter(id=####),
                label=ugettext_lazy("Groups"), required=True)

Thanks! 谢谢!

You can't do it in the field definition as you'll need the request object. 您将无法在字段定义中执行此操作,因为您将需要请求对象。 I think the only way to do it is to define formfield_for_dbfield on the admin class: 我认为唯一的方法是在admin类上定义formfield_for_dbfield

def formfield_for_dbfield(self, db_field, request, **kwargs):
    field = super(MyModelAdmin, self).formfield_for_dbfield(db_field, request, **kwargs)
    if db_field.name == 'groups':
        field.queryset = field.queryset.filter(user=request.user)
    return field

Haven't tested the code, so it might be wrong :-) 没有测试代码,所以可能是错误的:-)

With formfield_for_dbfield i have founded the answer :) 使用formfield_for_dbfield我已经找到了答案:)

admin.py admin.py

class MyModelAdmin(admin.ModelAdmin):
    form = MyModelForm
    ...
    def get_form(self, request, obj=None, **kwargs):
        kwargs['formfield_callback'] = partial(self.formfield_for_dbfield, request=request)
        return super(MyModelAdmin, self).get_form(request, obj, **kwargs)

    def formfield_for_dbfield(self, db_field, **kwargs):
        field = super(MyModelAdmin, self).formfield_for_dbfield(db_field, **kwargs)
        if db_field.name == 'group':
            field.queryset = field.queryset.filter(id__in=(kwargs['request'].user.groups.all()))
        return field

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